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Nutka1998 [239]

2 years ago

13

which is not part of maturity? excising self control, using good judgement, making impulsive decisions, being dependable

2 answers:

IgorLugansk [536]2 years ago

7 0

Answer:

using good judgement

Explanation:

cricket20 [7]2 years ago

4 0

Using good judgment hope this helps

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If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d

Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

$v_{i}=-44.5m/s\\v_{f}=55.5m/s$

Now we need to find the initial momentum

So

$P_{1}=m*v_{i}$

Substitute the given values

$P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s$

Now for final momentum

$P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s$

So the change in momentum is given as:

ΔP=P₂-P₁

$=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s$

ΔP=20 kg.m/s

3 0

4 years ago

What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?

Llana [10]

Answer:

Force = 100N

Explanation:

Force = mass × acceleration

3 0

3 years ago

The height of an object dropped from the top of a 64-foot building is given by h(t)=-16t^2+64. How long will it take the object

mojhsa [17]

Answer:

1.86 s

Explanation:

Given the expression

h(t) = -16t²+ 64...................... Equation 1

Where h = height of the object, t = time it will take the object to hit the ground.

Given: h = 64 foot.

We have to concert from foot to meters

If 1 foot = 0.3048 meters

Then, 64 foot = 0.3048×64 = 19.51 meters.

We substitute the value of h into equation

119.51 = -16t²+64

-16t² = 199.51-64

-16t² = 55.51

t² = 55.51/-16

t² = 3.469

t = √3.469

t = 1.86 s.

Hence it will take the object 1.86 s to hit the ground.

7 0

3 years ago

A rocket has initail mass M begins to move from space , with an exhaust constant speed . Find the mass of the rocket while has t

irina1246 [14]

Answer:

$m=\frac{m_{0}}{e}$

Explanation:

Equation of the rocket is,

$m\frac{dv}{dt} =F-v'\frac{dm}{dt}$

Here, v' is the relative velocity of rocket.

In space F is zero.

So,

$m\frac{dv}{dt} =-v'\frac{dm}{dt}\\dv=-v'\frac{dm}{m} \\v=-v'ln\frac{m}{m_{0} }$

Now the momentum can be obtained by multiply by m on both sides.

$P=-v'mln\frac{m}{m_{0} }$

Now for maxima, $\frac{dP}{dm}=0$

$-v'ln\frac{m}{m_{0} }-v'm\frac{m_{0}}{m }m_{0=0$

Now,

$ln(\frac{m}{m_{0} } )=-1\\\frac{m}{m_{0} }=\frac{1}{e} \\m=\frac{m_{0}}{e}$

Therefore, the mass of the rocket while having maximum momentum is $\frac{m_{0}}{e}$

3 0

4 years ago

A bicycle slows down when the rider applies the brakes.

aniked [119]

This is kinetic energy to heat energy

4 0

3 years ago

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