Answer:
Empirical formula is CH₄
Molecular formula = C₂H₈
Explanation:
Mass of carbon = 37.5 g
Mass of hydrogen = 12.5 g
Molecular weight = 32 g/mol
Molecular formula = ?
Empirical formula = ?
Solution:
Number of gram atoms of C = 37.5 g /12g/mol = 3.125
Number of gram atoms of H = 12.5 g / 1.008 g/mol= 12.4
Atomic ratio:
C : H
3.125/3.125 : 12.4 /3.125
1 : 4
C : H : = 1 : 4
Empirical formula is CH₄
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
n = 32 / 16
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₄)
Molecular formula = C₂H₈
Answer:
Answer is given below.
Explanation:
Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.
In cell representation, half cell present left to salt-bridge notation
is anodic system and another half cell present right to salt-bridge notation is cathodic system.
So anode is Cu and cathode is Ag.
oxidation: 
[reduction: 
]
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chemical equation: 
Oxidizing agent is that species which takes electron from another species. Here 
takes electron from Cu. Hence is the oxidizing agent.
Reducing agent is that species which gives electron to another species. Here Cu gives electron to . Hence Cu is the reducing agent.
Answer: fusion
Explanation:
Nuclear fission : It is defined as a process which involves the conversion of a heavier nuclei (which is an unstable nuclei) into two or more small nuclei (which is a stable nuclei) along with release of high amounts of energy.
Example: The energy released from the process of nuclear fission which is converted into electrical energy that is used in our homes and factories.
Nuclear fusion : It is defined as a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.
Example: It occurs in sun and stars where the isotopes of hydrogen called as Tritium and Deuterium combine together to form a neutron and a helium atom.
Answer:
<h3>AD=S×AT</h3>
Explanation:
<h3>the question is solving for AD </h3><h3>if s=AD/AT; THEN S/1=AD/AT </h3><h3>by cris cross multiplication </h3><h3>AD=S×AT</h3>
Removes smudges, leaves no after streaks
