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Komok [63]
2 years ago
12

PLEASE HELP I CAN'T FIGURE IT OUT

Chemistry
1 answer:
laiz [17]2 years ago
7 0

Answer:

11. F

12.H

16.J

20.K

21.i

Explanation:

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A mixture of 454 kg of applesauce at 10 degrees Celsius is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet
stira [4]

Explanation:

The given data is as follows.

           Mass of apple sauce mixture = 454 kg

           Heat added (Q) = 121300 kJ

 Heat capacity (C_{p}) of apple sauce at 32.8^{o}C = 4.0177 kJ/kg^{o}C

So, Heat given by heat exchanger = heat taken by apple sauce

                            Q = mC_{p} \Delta T

or,                    Q = mC_{p} (T_{f} - T_{i})  

Putting the given values into the above formula as follows.

                     Q = mC_{p} (T_{f} - T_{i})  

              121300 kJ = 454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)

                      T_{f} = 76.5^{o}C

Thus, we can conclude that outlet temperature of the apple sauce is 76.5^{o}C.

3 0
4 years ago
Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) 2Hg (l) + O
diamong [38]

hey there!:

2HgO (s) =>  2Hg (l) + O2 (g)

2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.

So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.

603 g of Hg = 603 / 200.6 = 3 moles

Percent yield = ( actual yield / theoretical yield) * 100

= ( 3/4) * 100

= 75 %

Hope this helps!

7 0
3 years ago
Read 2 more answers
What is Keq for the reaction N2 + 3H2 2NH3 if the equilibrium concentrations are [NH3] = 3 M, [N2] = 1 M, and [H2] = 2 M?
Licemer1 [7]

Answer : The correct option is, (D) k_{eq}=1.125

Explanation : Given,

Concentration of NH_3 = 3 M

Concentration of N_2 = 1 M

Concentration of H_2 = 2 M

The given balanced equilibrium reaction is,

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for equilibrium constant for this reaction will be,

K_{eq}=\frac{[NH_3]^2}{[N_2][H_2]^3}

Now put all the given values in this expression, we get the value of K_{eq}

K_{eq}=\frac{(3)^2}{(1)\times (2)^3}

K_{eq}=1.125

Therefore, the value of K_{eq} for the given reaction is, 1.125

5 0
3 years ago
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Explain how rocks salt forms in desserts
Fofino [41]
It is typically formed by the evaporation of salty water (such as sea water) which contains dissolved Na+ and Cl- ions. One finds rock salt deposits ringing dry lake beds, inland marginal seas, and enclosed bays and estuaries in arid regions of the world
4 0
3 years ago
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A 250.0 gram block is placed on a balance. The balance measures the mass of the block as 243.9 grams. What is the percent error
adell [148]
To compute the percent error, you divide the absolute difference between the actual value and the measured value with the actual value. Then, multiply it with 100 to get the percentage. The solution is as follows:

Percent error = (250 - 243.9)/250 * 100
Percent error = 2.44%
7 0
3 years ago
Read 2 more answers
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