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3 years ago

How are land-use laws in the United States different from the land-use laws inherited from England?

Physics

2 answers:

ycow [4]3 years ago

7 0

<span>Private property owners must allow for public access and use.</span>

Morgarella [4.7K]3 years ago

6 0

Answer is <span>
Private property owners in the United States can restrict public access to their land.</span>

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The unit of length most suitable for measuring the thickness of a cell phone is a . The unit of length most suitable for measuri

ArbitrLikvidat [17]

The answers include the following:

The unit of length most suitable for measuring the thickness of a cell phone is a meter.
The unit of length most suitable for measuring the height of a backyard tree is a meter.

<h3>What is Meter?</h3>

This is defined as the standard unit for measuring the length of a body and is denoted as m.

Height is a vertical type of length which is why meter was chosen as the most appropriate choice.

Read more about Meter here brainly.com/question/1578784

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2 years ago

A 4 kg bowling boll sliding to the right at 8 m/s has elastic head-on collision with another 4K bowling ball initially at rest.

MAXImum [283]

The energy would be transferred from the objects. Also do not forget, add direction to your answer.

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3 years ago

3. A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does

nikitadnepr [17]

Answer:

The extension of the second wire is $e_2 = 0.0024 \ m = 2.4 mm$

Explanation:

From the question we are told that

The length of the wire is $L = 3 \ m$

The elongation of the wire is $e = 1.2mm = \frac{1.2}{1000} = 0.0012 m$

The tension is $F = 200 \ N$

The length of the second wire is $L_2 = 6 \ m$

Generally the Young's modulus(Y) of this material is

$Y = \frac{stress}{strain }$

Where $stress = \frac{F}{A}$

Where A is the area which is evaluated as

$A = \pi r^2$

and $strain = \frac{extention}{length} = \frac{e}{L}$

$Y = \frac{\frac{F}{\pi r^2 } }{ \frac{e}{L} }$

Since the wire are of the same material Young's modulus(Y) is constant

So we have

$\frac{F * L }{r^2 e} = \pi * Y = constant$

$F * L = constant * r^2 e$

Now the ration between the first and the second wire is

$\frac{F_1}{F_2} * \frac{L_1}{L_2} = \frac{r*2_1}{r^2} * \frac{e_1}{e_2}$

Since tension , radius are constant

We have

$\frac{L_1}{L_2} = \frac{e_1}{e_2}$

substituting values

$\frac{3}{6} = \frac{0.0012}{e_2}$

$0.5 e_2 = 0.0012$

$e_2 = \frac{ 0.0012 }{0.5}$

$e_2 = 0.0024 \ m = 2.4 mm$

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3 years ago

Where is Jesus located, I would like to pay him a visit ;)

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Answer:

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rusak2 [61]

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