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Sindrei [870]
2 years ago
11

Jenna bought four composition notebooks in three pocket folders from the bookstore and paid $9.85. If the cost of a pocket folde

r is $1.15 less than the cost of a notebook, find the cost for a notebook.
Mathematics
2 answers:
PolarNik [594]2 years ago
7 0

Answer:

9.85 - 1.15 = 8.70

Step-by-step explanation:

you jus subtract :)  

siniylev [52]2 years ago
6 0

Answer:

  $1.90

Step-by-step explanation:

Let n represent the cost of a notebook. Jenna's purchase is ...

  4n +3(n -1.15) = 9.85

  7n - 3.45 = 9.85 . . . . . simplify

  7n = 13.30 . . . . . . . . . . add 3.45

  n = 1.90 . . . . . . . . . . . . divide by 7

The cost of a notebook is $1.90.

_____

<em>Additional comment</em>

The cost of a folder is 1.90 -1.15 = 0.75. The total purchase is ...

  4(1.90) +3(0.75) = 7.60 +2.25 = 9.85

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After lunch, you see the bumper cars and want to ride them. Here’s what the sign says:
NemiM [27]

Answer:

The option of 6 minutes with 8 tickets given more time for the money.

Step-by-step explanation:

Which one gives you more time for your money?

We have to find the time per ticket, which is the number of minutes divided by the number of tickets.

6 minutes: 8 tickets

6/8 = 0.(60/8) = 0.75 minutes per ticket.

8 minutes:12 tickets

8/12 = 2/3 = 0.(20/3) = 0.667 minutes per ticket.

So the option of 6 minutes with 8 tickets given more time for the money.

7 0
3 years ago
the standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. If x, y, and z eac
Studentka2010 [4]
For the units positions of all numbers we have:
z+7+5=4 \\ z+12=4
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
z+12=14 \\ z=2

For the tens positions of all numbers we have:
4+2+x+1=1 \\ 7+x=1
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
7+x=11 \\ x=4

Now we insert x and z to find out y:
42+27+45=y14 \\ 114=y14 \\ y=1

Now we need to find out the product of these three numbers:
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3 0
3 years ago
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

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