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3 years ago

Could an average star, such as our sun, become a neutron star? Explain your answer.

1 answer:

5 0

<span>No. Neutron stars are the remnants of very large stars that have supernova'd. Anything below 1.44 solar masses becomes a dwarf, anything above 5 solar masses becomes a black hole. Everything in between becomes a neutron star (or quark star, but it's not proven).</span>

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A filamentary conductor is formed into an equilateral triangle with sides of length carrying current i . find the magnetic field

arsen [322]

magnetic field due to a finite straight conductor is given by

$B = \frac{\mu_0 i}{4\pi r}(sin\theta_1 + sin\theta_2)$

here since it forms an equilateral triangle so we will have

$\theta_1 = \theta_2 = 60 degre$

also the perpendicular distance of the point from the wire is

$r = \frac{a}{2\sqrt3}$

now from the above equation magnetic field due to one wire is given by

$B = \frac{\mu_0 i}{4\pi \frac{a}{2\sqrt3}(sin60 + sin60)$

$B = \frac{\mu_0 i*2\sqrt3}{4\pi a}(\sqrt3)$

$B = \frac{3\mu_0 i}{2\pi a}$

now since in equilateral triangle there are three such wires so net magnetic field will be

$B = \frac{9\mu_0 i}{2\pi a}$

5 0

3 years ago

A group of college students eager to get to Florida on a spring break drove the 710-mi trip with only minimum stops. They comput

Elis [28]

Answer:

Time taken for trip = 12.74 hour (Approx)

Explanation:

Given:

Distance of trip = 710-mi

Average speed for the trip = 55.7 mi/h

Find:

Time taken for trip = ?

Computation:

⇒ Time = Distance / Speed

⇒ Time taken for trip = Distance of trip / Average speed for the trip

⇒ Time taken for trip = 710-mi / 55.7 mi/h

⇒ Time taken for trip = 12.74 hour (Approx)

7 0

3 years ago

to move a resting box of 100 Newton on the ground with kinetic friction coeficient of 0,250 is applied a force of 60 N horizonta

krok68 [10]

Work is calculated by multiplying force by the distance that the object had moved. The applied force is 60 N, moving the object by 10 m. Thus, the work does is 600 J. For the friction force which is equal to,
100N x 0.250 = 25.0 N
the work done is,
W = (60 N - 25 N) x 10 m = 350 J
The kinetic energy of the box can be equated to this force. Thus, the answer is also 350 J.

6 0

3 years ago

The distance between slits in a double-slit experiment is decreased by a factor of 2. If the distance between fringes is small c

Elodia [21]

Answer:

the distance between adjacent fringes is increased by a factor o 2

Explanation:

To find how the distance between fringes is modified you can use the following formula for the calculation of the distance between fringes:

$\Delta y=\frac{\lambda D}{d}$

D: distance to the screen

d: distance between slits

λ: wavelength of the light

if d is decreased by a factor of 2, that is d'=1/2d, you have:

$\Delta y'=\frac{\lambda D}{d'}=\frac{\lambda D}{(1/2)d}=2\Delta y$

hence, the distance between adjacent fringes is increased by a factor o 2

4 0

3 years ago

A body of mass 1.0 kg initially at rest slides down an incline plane that is 1.0 m high and 10.0 m long. If the body experiences

Ksivusya [100]

Answer:

answer is

Explanation:

because

6 0

3 years ago