The angular frequency of the wave is determined as 75.4 rad/s.
<h3>
What is wave function?</h3>
A wave function is a mathematical equation for the motion of the wave.
y(x, t) = A sin(kx + ωt + Φ)
where;
- ω is angular speed
- k is angular wavenumber
- Φ is phase angle
<h3>What is angular frequency?</h3>
The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.
<h3>Angular frequency</h3>
ω = 2πf
ω = 2π(12)
ω = 75.4 rad/s
Thus, the angular frequency of the wave is determined as 75.4 rad/s.
Learn more about angular frequency here: brainly.com/question/3654452
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Answer:
(a) 0.17 m
(b) 5.003 m
(c) 6.38 × 
N
(d) 7.37 ×
N
Explanation:
(a) The minimum value of 
will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.
(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.
<em>Hence, the maximum distance is 5.002 m</em>
(c) For minimum magnitude we use the minimum distance calculated in (a)
Minimum Distance = 0.17 m
For electrostatic force= 
×
(d) For maximum magnitude, we use the maximum distance calculated in (b)
Maximum Distance = 5.002 m
Using the formula for electrostatic force again:
F = 
F= 7.37×
N
Answer:
Physics
Explanation:
Explanation:
We can use the Theorem of Work (W) and Kinetic Energy (K):
W=ΔK=Kf−Ki
it basically tells us that the work done on our system will show up as change in Kinetic Energy:
We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:
F⋅d=Ff
45d=352
and so:
d=35245=7.8≈8m
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t
Case I
---------
When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C
Case II
----------
When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C
Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C
Case IV
-----------
When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C
Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
Answer:
R = 4.24 x 10⁻⁴ m
Explanation:
given,
mass of the person = 60.3-kg
mass of the bullet = 10 gram = 0.01 Kg
velocity of bullet = 389 m/s
angle made with the horizontal = 45°
using conservation of momentum.
M v + m u = ( M + m ) V
60.3 x 0 + 0.01 x 389 = (60.3 + 0.01) V
V = 0.0645 m/s
for calculation of range
R = 4.24 x 10⁻⁴ m
the distance actor fall is R = 4.24 x 10⁻⁴ m
