All categories

4 years ago

What is hidden during a lunar eclipse? Isn't the Moon hidden?

2 answers:

5 0

A lunar eclipse occurs when the Moon passes directly behind Earth and into its shadow. This can occur only when the Sun, Earth, and Moon are exactly or very closely aligned (in syzygy), with Earth between the other two. A lunar eclipse can occur only on the night of a full moon.

So yes the moon is hidden during a Lunar eclipse.

Setler [38]4 years ago

4 0

Here you go:

This light gets reflected onto the moon. ... The moon doesn't always hide completely behind Earth's shadow. During partial lunar eclipses, the sun, Earth and moon are slightly off in their alignment and so our planet's shadow engulfs just part of the moon.

Hope it helps you

Please mark me as Brainsliest

You might be interested in

Please help me and Can you show your work

RSB [31]

Answer:

7. 1ml = 20 drops

325ml = 6500

( 325 x 20 = 6500)

there are 6500 drops in a pepsi can

8. not sure sorry ; (

9. 1 mile per hour = 88 feet per minute

45 miles per hour = 3960 feet per minute

( 88 x 45 = 3960)

there are 3960 feet per minute in 45 miles per hour

4 0

3 years ago

Relationship between prism and lens

kozerog [31]

Answer:

In essence, optical lenses bend and focus light, known as refraction. Prism lenses, however, refract light a bit differently. ... Light passing through a prism will bend towards the base, while the image of the object viewed with the prism moves toward the peak.

Explanation:

5 0

3 years ago

A car is traveling at 60 mph. If the rate of speed increases 4 mph each hour,

Sauron [17]

Answer:

5 hours ................

6 0

3 years ago

Read 2 more answers

We have seen that when you generate a wave on a stretched spring, as long as the medium doesn’t change (that is, the tension and

TiliK225 [7]

Answer:

No, the acceleration is not always zero.

Explanation:

It does not mean that the acceleration of the particle is zero.

The velocity of wave is different from the velocity of particle.

The acceleration of wave is different from the acceleration of particle.

the acceleration of the particle is given by

$a =- w^2 y$

where, w is the angular frequency and y is the displacement from the mean position.

So, the acceleration is zero at mean position only and it varies as the position changes.

6 0

3 years ago

For a 50 kV anode voltage, what is the maximum photon energy of the x-ray radiation?

V125BC [204]

Answer:

The energy of photon, $E=8\times 10^{-15}\ J$

Explanation:

It is given that,

Voltage of anode, $V=50\ kV=50\times 10^3\ V=5\times 10^4\ V$

We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

$E=eV$

e is charge of electron

$E=1.6\times 10^{-19}\times 5\times 10^4$

$E=8\times 10^{-15}\ J$

So, the maximum energy of the x- ray radiation is $8\times 10^{-15}\ J$ . Hence, this is the required solution.

6 0

3 years ago