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krek1111 [17]
4 years ago
13

Which of the following properties did Rutherford use in his experiment?

Physics
1 answer:
Ronch [10]4 years ago
3 0

<u>Answer</u>:

(C) The positive charge of the alpha particles and the negative charge of the electrons  are the properties Rutherford used in his experiment

<u>Explanation</u>:

In his scattering experiment, scientist Ernest Rutherford used the property of positively charged alpha particles and negatively charge electrons. He performed this experiment by passing some of the alpha particles through a gold foil. The result was that the some alpha particles scattered while some passed through the gold foil without collision.

He concluded that the alpha particles are centrally positively charged and needed a large amount repelling force. This experiment of Rutherford is also known as Rutherford model of atom. This experiment helped him in doing so many other discoveries.

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What is the direction of the current flowing through the wire------left or right?
Sedbober [7]

Answer:

The direction in which a positive charge would move.

Explanation:

The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.

6 0
4 years ago
Read 2 more answers
Jonas has a 10.0 kg box, which he places on a scale inside an elevator. When the
Gennadij [26K]

Answer:

a = - 1.47 [m/s²], descending or going down

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F =  Forces applied [N]

m = mass = 10 [kg]

a = acceleration [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

-m*g + N = m*a\\

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force measured by the scale = 83.4 [N]

Now replacing:

-(10*9.81)+83.4=10*a\\-14.7=10*a\\a=-1.47[m/s^{2} ]

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

3 0
3 years ago
A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following fun
snow_lady [41]

The correct answer would be  1.375 < t < 3  i hope this helps anyone


8 0
3 years ago
Read 2 more answers
Calculate the longest wavelength visible to the human eye 164 kj mol
const2013 [10]
The working equation to be used here is the Planck's equation. This was derived using the wave behavior theory of the light and electromagnetic waves. According to this equation, electron transfer from orbital to orbital in discrete packets of energy called quanta. When an electron moves to a higher energy level, it absorbs energy. On the other hand, when it lowers to an energy level, it releases energy by emitting light. Hence, the wavelength of the light or magnetic wave can be determined.

E = hν = hc/λ, where ν is the frequency, λ is the wavelength, h is the Planck's constant equal to 6.626×10⁻³⁴ J-s and c is the speed of light equal to 3×10⁸ m/s.

Knowing the energy to be 164 kJ or 164,000 J, the wavelength is equal to

164,000 = (6.626×10⁻³⁴)(3×10⁸ m/s)/λ
λ = 1.212×10⁻³⁰ meters

8 0
4 years ago
What does <br>the length of a lens system depend on?​
AleksandrR [38]

Answer:

focal length depends on the radius of curvature, the refractive index of lens material, and the medium's refractive index in which the lens is placed

4 0
3 years ago
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