Answer:
The direction in which a positive charge would move.
Explanation:
The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.
Answer:
a = - 1.47 [m/s²], descending or going down
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
∑F = Forces applied [N]
m = mass = 10 [kg]
a = acceleration [m/s²]
Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.
By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

where:
g = gravity acceleration = 9.81 [m/s²]
N = normal force measured by the scale = 83.4 [N]
Now replacing:
![-(10*9.81)+83.4=10*a\\-14.7=10*a\\a=-1.47[m/s^{2} ]](https://tex.z-dn.net/?f=-%2810%2A9.81%29%2B83.4%3D10%2Aa%5C%5C-14.7%3D10%2Aa%5C%5Ca%3D-1.47%5Bm%2Fs%5E%7B2%7D%20%5D)
The acceleration has a negative sign, this means that the elevator is descending at that very moment.
The correct answer would be 1.375 < t < 3 i hope this helps anyone
The working equation to be used here is the Planck's equation. This was derived using the wave behavior theory of the light and electromagnetic waves. According to this equation, electron transfer from orbital to orbital in discrete packets of energy called quanta. When an electron moves to a higher energy level, it absorbs energy. On the other hand, when it lowers to an energy level, it releases energy by emitting light. Hence, the wavelength of the light or magnetic wave can be determined.
E = hν = hc/λ, where ν is the frequency, λ is the wavelength, h is the Planck's constant equal to 6.626×10⁻³⁴ J-s and c is the speed of light equal to 3×10⁸ m/s.
Knowing the energy to be 164 kJ or 164,000 J, the wavelength is equal to
164,000 = (6.626×10⁻³⁴)(3×10⁸ m/s)/λ
λ = 1.212×10⁻³⁰ meters
Answer:
focal length depends on the radius of curvature, the refractive index of lens material, and the medium's refractive index in which the lens is placed