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dezoksy [38]
3 years ago
13

When people exercise, they report feeling exhaustion when their body temp rises to 39.7 C a 68 kg man is running at 15 km/h on a

hot muggy day that he cant lose any heat to the environment his body temp starts at 37 Chow long can he run til he feels exhaustion
Physics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

111 seconds

Explanation:

From research, it takes 4200 J to raise 1 kg of body temperature. Which means that specific heat capacity of human body with is; c = 4200 J/Kg°C

We are told that the temperature starts at 37°C and rises to 39.7°C

Thus: Δt = 39.7 - 37 = 2.7°C

Amount of energy required is given by the formula;

q = mcΔt

We are given m = 68 kg

Thus;

q = 68 × 4200 × 2.7

q = 77112 J

From research, the human body is 25% efficient.

Formula for power with velocity is;

P = F × V

F = mg = 68 × 9.81

V = 15km/h = 4.167 m/s

P = 68 × 9.81 × 4.167

P = 2779.72 W

Since the human body is 25%

Then the power of the utilized is;

25/100 × 2779.72 = 694.93 W

Now, we now that;

Power = work done/time taken

694.93 = 77112/t

t = 77112/694.93

t = 111 seconds.

Thus, it will take home 111 seconds to feel exhausted

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QveST [7]

For the problem we will apply the concepts related to Newton's second law. Recall that this is defined as the product between mass and acceleration, and that in special cases, when the acceleration is equivalent to the force of gravity, the force is equivalent to the weight of the person. From these relationships we will find the mass, and then the acceleration with the given force.

F_w = mg

Here,

F_w= Force

m = Mass

g = Gravity

Replacing and rearranging we have that the mass is,

m = \frac{F_w}{g} = \frac{200}{9.81}

m = 20.387kg

Now using the value of the force, but solving for the acceleration with the previous value of the mass we have,

F = 30N

a = \frac{F}{m}

a = \frac{30}{20.387}

a = 1.47m/s^2

Therefore the acceleration of the box is 1.47m/s^2

8 0
3 years ago
A vector starts at the point (0.0) and ends at (3,-3). What is the angle of the displacement?
Naily [24]

Answer:

135degrees

Explanation:

Given that a vector starts at the point (0.0) and ends at (3,-3)

y component value = -3

x component value = 3

angle of the displacement theta = arctan(y/x)

theta = arctan(-3/3)

theta = arctan (-1)

theta = -45degrees

Since tan is negative in the second quadrant

theta = 180 - 45

theta = 135degrees

Hence the angle of the displacement is 135degrees

7 0
3 years ago
Consider the numbers 23.68 and 4.12. The sum of these numbers has ____ significant figures, and the product of these numbers has
damaskus [11]

Answer:multiplying will give us 7 significant figures and addition will give us 3 significant figures

Explanation:

After multiplying the two numbers they resulting value will give a value in its 4 decimal places because both given values are in 2 decimal places. The 4 dp is gotten by the addition of the decimal places of both given numbers (2+2) and

The result of its addition will give us a value in its 1dp and 3 significant figures since the addition of 23.68 and 4.12 will give us 27.8

7 0
3 years ago
Suppose you are standing such that a 35-foot tree is directly between you and the sun. If you are 7 feet tall and the tree casts
Juli2301 [7.4K]

Answer:

60 ft

Explanation:

The tree man and their shadow system forms two similar right angle triangles.

the figure is in the attachment.

let ∠BAC= θ

Therefore, in triangle ABC

tanθ = BC/AC= 35/75= 7/15

now in ΔAEF also

tanθ = EF/AE = 7/75-x= 7/15

solving we get x=60 ft

Now AC and FA are the shadows of the tree and the man respectively.

now FA =75-x=75-60= 15 ft

Therefore, the man must stand at a distance of 60 ft from the tree can you stand and still be completely in the shadow of the tree

3 0
4 years ago
Name the processes of going (a) from a solid to a gas and (b) from a gas to a solid.
marissa [1.9K]
The answer to the first one is sublimation.
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