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MariettaO [177]
3 years ago
11

If there is a negative sign in front of the Hooke's Law equation, what does the force, F, represent?

Physics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

Hooke's law, given by F=-kx is denoted with a negative sign to regard that the direction of restoring force that occurs opposite in direction of the force that caused the displacement x. F represents the force required to create a spring displacement of x.

Explanation:

As with many things in physics, the negative sign represents direction. In this case, after a spring is displaced a distance of x from equilibrium, the restoring force created by the spring will be in opposite direction of the force applied to move the spring there, represented by F.

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A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart
Musya8 [376]

1) 0.61 m/s^2

2) 13.9 s

Explanation:

1)

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

g=\frac{GM}{r^2} (1)

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

r=4R

where

R=6.37\cdot 10^6 m is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2

2)

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

g=0.61 m/s^2 is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s

4 0
3 years ago
A box on a table has these forces acting on it
umka21 [38]

Answer:

greater than 10 n

Explanation:

8 0
3 years ago
At 0.0 degrees Celsius, a wire cable is 410.0000 meters in length. When the temperature increased to 30.0 degrees Celsius, the w
zzz [600]

Answer: The coefficient of expansion for the wire 0.000028 (^oC)^{-1}.

Explanation:

Original length of the wire = L= 410.0000 m

Initial temperature =T_1=0.0^oC

Final Temperature = T_2=30.0^oC

Increase in Length of the wire = \Delta L=0.3444 m

\frac{\Delta L}{L}=\alpha _{L}\times \Delta T=\alpha _{L}\times (T_2-T_1)

\alpha _L=\frac{\Delta L}{L\times (T_2-T_1)}=\frac{0.3444 m}{410.0000 m\times (30.0^oC-0.0^oC)}

\alpha _L=0.000028 (^oC)^{-1}

The coefficient of expansion for the wire 0.000028 (^oC)^{-1}.

3 0
3 years ago
What is the speed of the object between 60 to 70 seconds?
lyudmila [28]

We have that the speed of the object between 60 to 70 seconds

V=\frac{d}{65}

From the question we are told

The speed of the object between 60 to 70 seconds

Generally the equation for Average speed   is mathematically given as

V=\frac{d}{t}

Where

t=\frac{60+70}{2}\\\\t=65seconds

Therefore

V=\frac{d}{65}

In conclusion

The speed of the object between 60 to 70 seconds

V=\frac{d}{65}

For more information on this visit

brainly.com/question/23379286?referrer=searchResults

5 0
3 years ago
A scuba diver measures an increase in pressure of around 10^5 Pa upon descending by 10 m, what is the change in force per square
IceJOKER [234]

Answer:

Explanation:

Given that, .

Pressure around scuba is

P = 10^5 Pa

1 Pa = 1 N/m²

Then

P = 10^5 N/m²

Descending height

h = 10m

Change in force per unit square centimetre

We know that,

Pressure = Force / Area

Then,

Force / Area is the required question we are finding

Then,

Force / Area = 10^5 N / m²

So, let convert the m² to cm²

100cm = 1m

(100cm)² = (1m)²

10⁴cm² = 1m²

Then,

Force / Area = 10^5 N/m² × 1m² / 10⁴cm²

Force / Area = 10 N/cm²

So, the force per unit square centimeters is 10.

7 0
3 years ago
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