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2 years ago

What local group of galaxies is the Milky Way part of?

Physics

1 answer:

Karo-lina-s [1.5K]2 years ago

5 0

The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C

<h3>What are Virgo Supercluster?</h3>

The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.

Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.

Learn more about Milky Way here:

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a person when asked to speak up,increases her sound level from 30dB to 60dB.The amount of power per unit area increased by? a)30

aivan3 [116]

Answer:

d) 1000 times

Explanation:

As we know that difference of sound level is given as

$L_2 - L_1 = 10 Log \frac{I_2}{I_1}$

so here we need to find the ratio of two intensity

it is given as

$Log\frac{I_2}{I_1} = \frac{(L_2- L_1)}{10}$

$Log\frac{I_2}{I_1} = \frac{60 - 30}{10}$

$Log\frac{I_2}{I_1} = 3$

now we have

$\frac{I_2}{I_1} = 10^3$

so it is

d) 1000 times

4 0

3 years ago

The asteroid 2007 VK184 has one chance in 2940 of hitting the Earth between the years 2048 and 2057. The asteroid is 130 meters

N76 [4]

Answer:

The average death rate for this type of event is closest to 350 people per event.

Explanation:

Between the years 2048 and 2057

Is 10 years. Since there is only one chance of event between these years, there is no point to consider it.

The total number of events = 2940 chances.

average death rate per event = total number of dead people divided by total number of events of occurrence.

1000000/2940 = 340.134

The average death rate for this type of event is therefore closest to 350 people per event

4 0

2 years ago

Charge X has twice as much charge as particle Y. The two charges are placed near each other. Compared to the force on particle X

Art [367]

The force on charge Y is the same as the force on charge X

Explanation:

We can answer this problem by applying Newton's third law of motion, which states that:

"When an object A exerts a force on object B (action force), then object B exerts an equal and opposite force on object A (reaction force)"

In this problem, we can identify object A as charge X and object B as charge Y. The magnitude of the electrostatic force between them is given by

$F=k\frac{q_x q_y}{r^2}$ (1)

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_x, q_y$ are the two charges

r is the separation between the two charges

According to Newton's third law, therefore, the magnitude of the force exerted by charge X on charge Y is the same as the force exerted by charge Y on charge X (and it is given by eq.(1)), however their directions are opposite.

Learn more about Newton's third law:

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6 0

2 years ago

A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als

Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

$V_T = V_1 + V_2$