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Oduvanchick [21]
4 years ago
10

21 of 35 Review A friend of yours is loudly singing a single note at 401 HzHz while racing toward you at 23.0 m/sm/s on a day wh

en the speed of sound is 343 m/sm/s . Part A What frequency do you hear
Physics
1 answer:
Ipatiy [6.2K]4 years ago
5 0

Answer:

The frequency of the sound note as heard = 429 Hz

Explanation:

The frequency of sound waves as heard from a distance for a sound wave coming towards one at v₀ m/s and whose real frequency is f₀ is given by

+f = f₀/[1 - (v₀/v)]

+f = frequency of sound as heard from the distance away = ?

f₀ = real frequency of sound = 401 Hz

v₀ = velocity at which the sound source is moving towards the reference point = 23.0 m/s

v = velocity of sound waves = 343 m/s

+f = 401/[1 - (23/343)]

+f = 429 Hz

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Un tubo cilindrico hueco de cobre mide 3 m de longitud tienen un diametro exterior de 4cm y un diametro interior de 2 cm¿cuanto
Irina-Kira [14]

Answer:

 W = 9.93 10² N

Explanation:

To solve this exercise we must use the concept of density

           ρ = m / V

the tabulated density of copper is rho = 8966 kg / m³

let's find the volume of the cylindrical tube

           V = A L

           V = π (R_ext  ² - R_int ²) L

let's calculate

          V = π (4² - 2²) 10⁻⁴  3

          V = 1.13 10⁻²  m³

         m = ρ V

        m = 8966 1.13 10⁻²

        m = 1.01 10² kg

the weight of the tube

        W = mg

         W = 1.01 10² 9.8

         W = 9.93 10² N

4 0
3 years ago
If Mrs. Reichelt throws a chromebook, because it won't login correctly, with a force of 8N, and the chromebook accelerates at 5m
suter [353]

Answer:

1.6 kg

Step-by-step Solution:

Since Force = mass × acceleration we have:

F = 8N

a= 5 m/s^2

m = ?

By plugging the values above into F=ma we obtain:

F=ma\\\\8=m(5)\\\\\frac{8}{5}=\frac{m(5)}{5}\\\\m=\frac{8}{5}=1.6

Therefore, the Chromebook has a mass of 1.6 kilograms.



7 0
3 years ago
In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat
olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

v_f = 0

now we can use kinematics top find the acceleration of the bullet

v_f^2 - v_i^2 = 2 a d

so we have

0 - 55^2 = 2(a)(1.34)

a = -1128.7 m/s^2

now by Newton's II law we know that

F = ma

so we have

F = (0.052)(-1128.7)

F = -58.7 N

8 0
3 years ago
Two people carry a heavy electric motor by placing it on a light board 2.45 m long. One person lifts at one end with a force of
maxonik [38]

Answer:

W=1055N

Explanation:

In order to solve this problem, we must first do a drawing of the situation so we can visualize theh problem better. (See attached picture)

In this problem, we will ignore the board's weight. As we can see in the free body diagram of the board, there are only three forces acting on the system and we can say the system is in vertical equilibrium, so from this we can say that:

\sum F=0

so we can do the sum now:

F_{1}+F_{2}-W=0

when solving for the Weight W, we get:

W=F_{1}+F_{2}

and now we can substitute the given data, so we get:

W=410N+645N

W=1055N

5 0
3 years ago
Next
natta225 [31]

Answer:

maybe it is the first one

7 0
3 years ago
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