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zheka24 [161]
3 years ago
12

What is one factor that helps keep the planets and other solar system objects in orbit around the sun?

Physics
2 answers:
pshichka [43]3 years ago
7 0
The answer is D<span>.the gravitational force between the sun and each object in the solar system</span>
zhuklara [117]3 years ago
3 0
D the sun`s gravitational force and the planet`s gravitational force keeps us in our spots
You might be interested in
An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of
blondinia [14]

Answer:

v = 12.12 m/s      

Explanation:

It is given that,

Radius of circle, r = 30 m

The coefficient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

5 0
4 years ago
I will give brainiest to the first person that gives a somewhat sensible answer, but for the love of god, someone answer!
Olegator [25]
It’s c Because is the one the makes the most sense
7 0
3 years ago
the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t
Eddi Din [679]
Mass will remain constant on both planet, let mass of the object be "m".
let x be the <span>acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is </span><span>acceleration due to gravity on the surface of earth
</span>⇒350 =  m *  9.8
⇒m = 350  /  9.8                        .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134  =   m   *  x                           .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x     =   (134  *  9.8) / 350
⇒  x   =   3.572 m/s²
7 0
4 years ago
I NEED HELP PLEASE THANKS! :)
Nady [450]

Answer:

0.962 s

Explanation:

Speed = frequency × wavelength

v = fλ

2.60 m/s = f (2.50 m)

f = 1.04 Hz

Period = 1 / frequency

T = 1/f

T = 1 / (1.04 Hz)

T = 0.962 s

7 0
3 years ago
Older railroad tracks in the U.S. are made of 12-m-long pieces of steel. When the tracks are laid, gaps are left between section
____ [38]

Answer: ∆L = 0.49cm ≈ 0.50cm

Therefore there should be 0.5 cm gap between each piece of steel.

Explanation:

Thermal expansion of steel is the increase in size of steel as a result of increased temperature. It can be represented by the mathematical expression:

∆L = L(k)∆T .....1

Where;

∆L is the change in length

L is the initial length

∆T is the change in temperature

k is the specific Linear expansion coefficient.

Given;

L = 12m

∆T = 50°C - 16°C = 34°C

k (for steel) = 1.2 × 10^-6 /C

Substituting the values into the equation 1

∆L = 12 × 34 × 12×10^-6

∆L = 4896 × 10^-6 m

∆L = 0.49cm ≈ 0.50cm

Therefore there should be 0.5 cm gap between each piece of steel.

6 0
3 years ago
Read 2 more answers
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