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____ [38]
3 years ago
15

Which compound is an alkyne? (1) C2H2 (3) C4H8 (2) C2H4 (4) C4H10

Chemistry
2 answers:
Romashka [77]3 years ago
6 0

Answer: C_2H_2

Explanation:

Saturated hydrocarbons are defined as the hydrocarbons in which a single bond is present between carbon and carbon atoms. The general formula for these hydrocarbons is C_nH_{2n+2} and are called as alkanes.

Unsaturated hydrocarbons are defined as the hydrocarbons which have double or triple covalent C-C bonds. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is C_nH_{2n} and C_nH_{2n-2} respectively.

C_4H_8 and C_2H_4 are alkenes.

C_4H_{10} is an alkane.

Thus C_2H_2 with general formula C_nH_{2n-2} is an alkyne.

olga2289 [7]3 years ago
5 0
The answer is C2H2 because an alkyne compound consists of a series of unsaturated hydrocarbons with a triple bond. 
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What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +
Mademuasel [1]

Answer: \Delta S^{0} for the reaction is -186.75 J/K

Explanation:

Change in entropy (\Delta S^{0}) for the given reaction under standard condition is given by-

\Delta S^{0}= [3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]

So \Delta S^{0} = [3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol] = -186.75 J/K

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3 years ago
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Why krypton and noble gas are not used in airships using the periodic table?
WITCHER [35]

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Explanation:

3 0
3 years ago
What is the answer to...
adoni [48]

Answer: short answer short 0.65 / 5.37

15% NaOH by mass is 15g of NaOH in (100-15)g of solution.

No. Of moles of NaOH in solution = 0.65

No of moles of Water in solution = 4.72

Mole Fraction =  

(

(Moles of Solvent)

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)

OR

(

(Moles of Solvent)

Total Number Of Moles

)

= 0.65 / 5.37

= 0.121

Explanation:

Hope this helped

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3 years ago
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