Question

A 60-W light bulb consumes 60 W of electrical power. It radiates almost all of this power, some of it in the form of visible light and some of it in the form of heat. Find the intensity of the total radiated energy (light and heat) at a distance 3.7 m from the light bulb.\

Answer 1

Answer:

0.349W/m²

Explanation:

We can use the intensity formula [ I = P/T ].

= P / 4πr²

= 60/4π(3.7)²

= 60/4(3.14)(13.69)

= 60/4(42.9866)

= 60/171.9464

≈ 0.349W/m²

Best of Luck!