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eimsori [14]
2 years ago
5

If the atomic mass of Sodium-18 is 18.02597 u, what is the binding energy?

Physics
1 answer:
Klio2033 [76]2 years ago
8 0

Answer:

<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>

Explanation:

<h3>Greetings !</h3>

Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.

<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3><u>Given</u><u> </u><u>values</u></h3>
  • m= 18.02597
  • c=3.00×10⁸ms¯¹

<h3><u>required </u><u>value</u></h3>
  • Eb=?

<h3><u>Solution:</u></h3>
  • Eb=(Δm)c²
  • Eb=(18.02597)*(3.00*10⁸ms¯¹
  • Eb=5.407791*10⁹J

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Explanation:

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Knowing this, let's substitute the values and find h from (1):

0.375 g=(3 g)2^{\frac{-1h}{H}} (2)  

\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}} (3)  

Applying natural logarithm in both sides:

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Clearing H:

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