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OLga [1]
3 years ago
8

What do we call the tide that occurs when constructive interference between lunar and solar bulges produces a large tidal range?

Physics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

Spring Tide

Explanation:

Normal tidal sizes become slightly larger during complete or new moons— which arise when the Moon, the sun, and the moon are almost in a straight line. It occurs two times a month. The moon looks new (dark) when it's exactly between the sun and the Earth. Once the Moon would be between the sun and earth the moon appears complete. On both situations, the sun's gravitational pull is "added up" to the Earth's gravitational pull n the moon, allowing the oceans to boom a little more than normal. This equals higher tides are marginally higher and low tides are somewhat lower than usual.

This is called as spring tide.

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A 6.0 m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 Hz, the wavelength is 0.40
MrRissso [65]

Answer:

a) t = 0.0185 s = 18.5 ms

b) T = 874.8 N

Explanation:

a)

First we find the seed of wave:

v = fλ

where,

v = speed of wave

f = frequency = 810 Hz

λ = wavelength = 0.4 m

Therefore,

v = (810 Hz)(0.4 m)

v = 324 m/s

Now,

v = L/t

where,

L = length of wire = 6 m

t = time taken by wave to travel length of wire

Therefore,

324 m/s = 6 m/t

t = (6 m)/(324 m/s)

<u>t = 0.0185 s = 18.5 ms</u>

<u></u>

b)

From the formula of fundamental frquency, we know that:

Fundamental Frequency = v/2L = (1/2L)(√T/μ)

v = √(T/μ)

where,

T = tension in string

μ = linear mass density of wire = m/L = 0.05 kg/6 m = 8.33 x 10⁻³ k gm⁻¹

Therefore,

324 m/s = √(T/8.33 x 10⁻³ k gm⁻¹)

(324 m/s)² = T/8.33 x 10⁻³ k gm⁻¹

<u>T = 874.8 N</u>

8 0
3 years ago
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Natali [406]

Answer:

The answer is 4x³ + 6x²

<u>-TheUnknownScientist</u><u> 72</u>

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Alina [70]

Answer:

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Explanation:

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2 years ago
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