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OLga [1]
3 years ago
8

What do we call the tide that occurs when constructive interference between lunar and solar bulges produces a large tidal range?

Physics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

Spring Tide

Explanation:

Normal tidal sizes become slightly larger during complete or new moons— which arise when the Moon, the sun, and the moon are almost in a straight line. It occurs two times a month. The moon looks new (dark) when it's exactly between the sun and the Earth. Once the Moon would be between the sun and earth the moon appears complete. On both situations, the sun's gravitational pull is "added up" to the Earth's gravitational pull n the moon, allowing the oceans to boom a little more than normal. This equals higher tides are marginally higher and low tides are somewhat lower than usual.

This is called as spring tide.

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The record for the highest speed achieved in alaboratory for a
Ira Lisetskai [31]

Answer:

0.000234 seconds

Explanation:

Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m

We can start by calculating the angular speed of the rod:

\omega = \frac{v}{r} = \frac{2010}{0.075} = 26800 rad/s

Since one revolution equals to 2π rad. The speed in revolution per second must be

26800 / 2π = 4265 revolution/s

The number of seconds per revolution, or period, is the inverse:

1/4265 = 0.000234 seconds

3 0
3 years ago
A 3.0-A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the
harina [27]

Answer:

R=2.78\ \Omega

Explanation:

Given that,

The current flowing in the circuit, I = 3 A

The power of the battery, P = 25 W

We need to find the resistance of the battery. We know that the power of the battery is given by the formula as follows :

P=I^2R

Put all the values to find R.

R=\dfrac{P}{I^2}\\\\R=\dfrac{25}{(3)^2}\\\\R=2.78\ \Omega

So, the resistance is equal to 2.78\ \Omega.

7 0
3 years ago
Which part of the eye holds eye color?
Anna [14]

Hi, it’s the iris. Hope this helped u

6 0
3 years ago
7. How many 1.00 µF capacitors must be connected in parallel to store a charge of 1.00 C with a potential of 110 V across the ca
Misha Larkins [42]

Answer:

q = C V    charge on 1 capacitor

q = 1 * 10E-6 * 110 = 1.1 *  10E-4  C per capacitor

N = Q / q = 1 / 1.1 * 10E-4  = 9091 capacitors

8 0
3 years ago
What types of elements are useful for dating materials?
Semenov [28]
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Accuracy of radiometric dating.
Closure temperature.
The age equation.
Uranium–lead dating method.
Samarium–neodymium dating method.
Potassium–argon dating method.
<span>Rubidium–strontium dating method.</span></span>
3 0
3 years ago
Read 2 more answers
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