A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
Answer:
28.81 m
Explanation:
Ff = -123
m * a = -123
(29.8+10.3) * a = -123
a = -123/40.1 = -3.07
We know,
v^2 = u^2 + 2as
0^2 = 13.3^2 + 2*(-3.07)*s
s = 176.89/6.14 = 28.81
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Answer:
Explanation:
1.)acceleration= final velocity-initial velocity/time
90m/s-0m/s /3seconds
=30m/s^2
2.) distance= speed*time
90m/s*3seconds
=270m
Answer:
4.88 miles
Explanation:
7.85km * (.621miles/km) = 4.88 miles
