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2 years ago

11

The product of a number, x, and 3 is six more than the product of the number and 2.

1 answer:

Pavel [41]2 years ago

7 0

Answer:

3x = 6 + 2x

Step-by-step explanation:

The word "product" defines multiplication between two numbers. Those numbers are x and 3. The word "is" defines the "equal sign". The word "more" defines addition. Now, using these definitions, let's create an equation.

=> (3 × x) = 6 + (2 × x)
=> 3x = 6 + 2x

Hence, Option C is correct.

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What is the area of a circle, if it's radius is 2cm?

slega [8]

25.13cm^2 or 8pi. The radius of a circle is 2 x pi x r^2. R is the radius. 2 x pi x 2^2cm -> 2 x pi x 4cm -> 8cm x pi -> 25.13cm^2. Leaving the answer in terms of pi would be 8pi.

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3 years ago

A scale drawing of a rectangular painting is shown below. In the drawing, side E is 10 centimeters and side D is 24 centimeters.

Jobisdone [24]

Answer:

Side D is 0.78 feet (to 2 s.f.)

Step-by-step explanation:

In the Scale Drawing, side D=24 centimeters

1 foot = 30.48cm

x foot = 24 cm

Therefore:

24 X 1 = 30.48 X x

x= 24/30.48 =0.7874 feet

Side D is 0.78 feet (to 2 s.f.)

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3 years ago

Please help. I will give brainliest immediately.

DerKrebs [107]

Answer:

I'm pretty sure it is d, 5/22

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2 years ago

An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d

denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is $6\times 3\times 2\ ft$

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. $w\times 2w\times h=36$

$h=\frac{18}{w^2}$

The equation form when top is open,

$f(w)=2w^2+2wh+2(2w)h$

Substitute the value of h,

$f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})$

$f(w)=2w^2+\frac{36}{w}+\frac{72}{w}$

$f(w)=2w^2+\frac{108}{w}$

Derivate w.r.t 'w',

$f'(w)=4w-\frac{108}{w^2}$

For critical point put it to zero,

$4w-\frac{108}{w^2}=0$

$4w=\frac{108}{w^2}$

$w^3=27$

$w^3=3^3$

$w=3$

Derivate the function again w.r.t 'w',

$f''(w)=4+\frac{216}{w^3}$

For w=3, $f''(3)=4+\frac{216}{3^3}=12 >0$

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = $\frac{18}{3^2}=2\ ft$

Therefore, the dimensions of the box that minimize the materials used is $6\times 3\times 2\ ft$

4 0

3 years ago

Name the Property of Equality that justifies the statement: If m<A + M<B = M<C. Then, M<A = M<C - M<B

adoni [48]

The subtracton property of equality allows you to subtract the same amount from both sides of an equation without changing the truth of the equation.

5 0

2 years ago