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hichkok12 [17]
2 years ago
15

A 1,000 kg car is moving at 20 m/s, and slams into a building before coming to a halt.

Physics
1 answer:
ale4655 [162]2 years ago
7 0

Hi there!

We can calculate linear momentum using the following:
\large\boxed{p = m v}

p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)

Calculate:

p = 1000 * 20 = 20000 kg\frac{m}{s}

Now, we can relate force, time, and momentum with the following:
\large\boxed{I = Ft}\\\\

I = Impulse (kgm/s)
F = Force (N)
t = time (s)

Rearrange to solve for force:
F = \frac{I}{t}

The impulse is equal to the change in momentum. Since the car comes to a halt, all of its momentum is lost, so:

I = \Delta p = p_f - p_i = 0 - 20000 = -20000

Solve:
F = \frac{-20000}{0.5} = \boxed{-40000N}

**Negative force since the positive direction is towards the wall, and the negative direction is away from the wall.

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You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th
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Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

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Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

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The acceleration of the sled is given as follows;

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The acceleration of the sled, a = 0.4 m/s²

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The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

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