<u>Analysing the Question:</u>
We are given the balanced equation:
C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O
from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>
<u>Moles of Glucose used in the reaction:</u>
Molar mass of Glucose = 180 grams / mol
Given mass of Glucose = 1 gram
Mole of Glucose = Given mass / Molar mass
Moles of Glucose = 1 / 180 moles
<u>Mass of Oxygen required:</u>
We know that for every mole of Glucose, we need 6 moles of Oxygen
So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen
Mass of 1 / 30 moles of Oxygen:
Mass = Molar mass * number of moles
Mass of Oxygen = 32 * 1/30
Mass of Oxygen = 32 / 30
Mass of Oxygen = 1.06 grams
