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Tomtit [17]
2 years ago
10

A sample of the alloy “electrum” is 62% silver and 38% gold by mass; mass of part/

Chemistry
1 answer:
Tanzania [10]2 years ago
5 0

Answer:

c

Explanation:

edge 2022

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When given any reaction how do I figure out the products and then balance it?
Tju [1.3M]
AB(aq)+C  >A +CB(aq)
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5 0
3 years ago
Question 2 (2 points)
inysia [295]

Answer:

v = 46.5 m/s

Explanation:

Given data:

Mass of car = 1210 kg

Momentum of car = 56250 kg m/s

Velocity of car = ?

Solution:

Formula:

p = mv

p = momentum

m = mass

v = velocity

Now we will put values in formula:

56250 kg m/s  = 1210 kg × v

v = 56250 kg m/s / 1210 kg

v = 46.5 m/s

So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.

5 0
3 years ago
What are the 3 primary consumers and what are the 3 secondary consumers
goldenfox [79]
Primary:
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8 0
3 years ago
Iron is obtained commercially by the reaction of hematite (Fe2O3) with carbon monoxide. How many grams of iron are produced if 1
kherson [118]
 <span>CO is the limiting reactant 
( 25.0 x 3 = 75 moles of CO are required) 

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5 0
3 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
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