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2 years ago

PLEASE HELP WILL GIVE BRANLIEST!!!!!!

Chemistry

1 answer:

Tanzania [10]2 years ago

8 0

Answer:

The peel

Explanation:

the liquid cant go through the peel

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What does the pacific tsunami warning system use to detect tsunamis ?

S_A_V [24]

Answer:

Explanation:

Their are pressure sensers in the water that will detect high pressure and set of scales that are currently detecting semic waves and trigger sierns.

7 0

2 years ago

Helpppppp i hate chemistry

BigorU [14]

Answer:

The first option: Strontium Fluorate.

Explanation:

because Fluorine and oxygen combines to make fluorate, Strontium stays the same.

p.s: i need help in geo and there's an exam tomorrow.

8 0

3 years ago

train travel from hong kong to beijing it traveled at an average speed of 160 km/m in the first 4 hours. after that it traveled

Nonamiya [84]

Answer:

7 hours

Explanation: step 1. 160x4=640

step 2. 1180-640=540

step 3. 540÷180=3

step 4. 3+4=7

5 0

3 years ago

Read 2 more answers

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago

What occurs at one of the electrodes in both an electrolytic cell and a voltaic cell?

rjkz [21]

Anode- oxidization

Cathode-reduction

3 0

2 years ago