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Nana76 [90]
3 years ago
9

PLEASE HELP WILL GIVE BRANLIEST!!!!!!

Chemistry
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

The peel

Explanation:

the liquid cant go through the peel

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What are the uses of Acetylene ?<br>​
xxMikexx [17]

Answer:

it is used for welding and cutting

7 0
3 years ago
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How many hydrogen bonds can CH2O make to water
VladimirAG [237]
Hydrogen bonds are not like covalent bonds. They are nowhere near as strong and you can't think of them in terms of a definite number like a valence. Polar molecules interact with each other and hydrogen bonds are an example of this where the interaction is especially strong. In your example you could represent it like this: 

<span>H2C=O---------H-OH </span>

<span>But you should remember that the H2O molecule will be exchanging constantly with others in the solvation shell of the formaldehyde molecule and these in turn will be exchanging with other H2O molecules in the bulk solution. </span>

<span>Formaldehyde in aqueous solution is in equilibrium with its hydrate. </span>

<span>H2C=O + H2O <-----------------> H2C(OH)2</span>
5 0
3 years ago
When a sample of ca(s) loses 1 mole of electrons in a reaction with a sample of o2(g) the oxygen?
Stolb23 [73]
The reaction involved in present case is:

Net Reaction: Ca   +    1/2 O2    →         CaO. ..................(1)

In terms of oxidation and reduction, the reaction can be shown at

Oxidation: Ca     →       Ca2+      +       2e- .................(2)
Reduction: 1/2O2    +   2e-      →      O2-...................(3)

From, reaction 1 it can be seen that 1 mol of Ca reacts with 1/2 mol of O2 to form 1 mol of CaO.

From, reaction 2 it can be seen that 1 mol of Ca, generates 2 mol of e-.

Thus, when 1/2 mol of Ca is used in reaction, it will lose 1 mol of electrons.
6 0
3 years ago
Read 2 more answers
Find the mass of each of these substances? 2.40 mol NaOH
damaskus [11]
Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0
4 years ago
How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i
bagirrra123 [75]

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O  

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

7 0
3 years ago
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