The concentration of the original calcium ions is 0.005 M
<h3>What is concentration?</h3>
The term concentration has to do with the amount of substance in solution. We know that the concentration can be measured in a lot of units such as mole/litre, grams per litre, percentage and so on.
As such we have the equation;
Ca^2+(aq) + (NH4)2CrO4(aq) --------> CaCrO4(s) + 2NH4^+(aq)
Number of moles of the precipitate = 346.7 * 10^-3 g/156 g/mol
= 0.0022 moles
Now;
1 mole of Ca^2+ produces 1 mole of CaCrO4 hence 0.0022 moles of CaCrO4 was produced by 0.0022 moles of CaCrO4.
Given that the volume of the solution is 0.440 L, the concentration of the solution is; 0.0022 moles/0.440 L
= 0.005 M
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Answer:
The correct answer is 1.778 milligrams per liter.
Explanation:
Based on the given information, the concentration of chlorine gas given is 27 pounds or 27*453.59 = 12327.93 grams.
The quantity of water given is 750000 gallons or 750000 * 3.754 = 2815500 L
The concentration of chlorine used up by the microorganism is 2.6 mg/L or 0.0026 gm/L.
Thus, for 2815500 L of water, the amount of chlorine used is,
= 2815500 * 0.0026
= 7320.3 grams
The left quantity of chlorine is 12327.93 - 7320.3 = 5007.63 grams
The concentration of residual chlorine is,
= 5007.63 g/2815500 = 0.00177859 or 1.778 mg/L.
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