If there is no slipping or skidding going on, then for each revolution, the tire rolls along the ground a distance equal to the tire's circumference.
Circumference of the tire = 2 · π · Radius .
During the same revolution, the small stone stuck in the tread travels in a big semicircular arc that's <em>(2 · π · r)</em> long. (roughly 6.28r)
Answer:
Explanation:
This problem can be solved with the conservation of the momentum.
If the ball is fired upward, the momentum before and after the ball is fired must conserve. Hence, the speed of the ball is the same that the speed of the car just in the moment in wich the ball is fired.
Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.
If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.
HOPE THIS HELPS!!
Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2<span>) electrons.</span>