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Leto [7]
3 years ago
6

A fighter jet lands on the flight deck of an aircraft carrier that has a length of 300.0 m. The jet must reduce its speed from a

bout 153 km/h to exactly 0 km/h in 2.0 s. What is the jet’s acceleration?
Physics
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

-76.5m/s²

Explanation:

Vf=Vi+at

When equation is rearranged to solve for acceleration

a=(Vf-Vi)/t

a=(0-153)/2

a=-76.5

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At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50
Allushta [10]
The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
E=K+U= \frac{1}{2}mv^2 +mgh
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ
6 0
3 years ago
If a person walks 1km north , 5 km West , 3km south and 7km east, find the resultant displacement vector
raketka [301]

Y = +1-3 = -2  

X = -5+7 = +2  

D = √2^2-2^2 = 2√1+1 = 2√2 km

3 0
3 years ago
Jordan wants to know the difference between using a 60-W and 100-W lightbulb in her lamp. She calculates the energy it would tak
Andreas93 [3]

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

E = P*t

Where P is the power and t is the time

For the 60 W lightbulb:

E_{60} = P*t = 60 W*30 s = 1800 J

For the 100 W lightbulb:

E_{100} = P*t = 100 W*30 s = 3000 J

Hence, the difference in the amount of energy transferred is:

E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

4 0
3 years ago
A 6.7 kg object moves with a velocity of 8 m/s. What's its kinetic energy? A. 26.8 J B. 214.4 J C. 167.5 J D. 53.6 J
expeople1 [14]
KE= .5*M*V^2
.5*6.7*8^2
=214.4 Joules
7 0
4 years ago
Read 2 more answers
It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone? ​
zepelin [54]

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

Work=Power\times time

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

Work=342J/s\times 59s=20178J

Thus the work done on the flagstone is 20178 J

5 0
3 years ago
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