How old was this tree when it was cut down?

Type the correct answer in each box. Spell all words correctly.

There’s nothing there?

8 0

3 years ago

Give the products of the reaction of butanal, with: (a) sodium borohydride, in methanol (b) hydrogen cyanide, with catalytic cya

miss Akunina [59]

Answer:

Answers are given below

Explanation:

(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.

So, butanal produces butanol on reaction with sodium borohydride in methanol.

(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.

(c) Aldehydes are oxidized by potassium dichromate in dil. sulphuric acid to produce carboxylic acid.

(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.

(e) Aldehyde gives condensation reaction with $CH_{3}CH_{2}NH_{2}$ to produce imine.

Structures of products for the given reaction has been shown below.

4 0

3 years ago

Please answer with an actual answer and not just put a random word ^-^

WARRIOR [948]

Which eclipse was modeled when the large ball was between the small ball and the light?

The model is a "Lunar Eclipse" (If it was talking about the earth, then yes, it is a lunar eclipse).

Which eclipse was modeled when the small ball was between the large ball and the light?

The model is a "Solar Eclipse".

What does the large ball represent?

The earth.

What does the small ball represent?

The moon.

What does the light source represent?

The sun.

Hope this helps!~ <3

(I can't draw so sorry.)

6 0

3 years ago

The enthalpy of combustion of gasoline (C8H18) is 5471 kJ mol-1. How much heat will be produced by burning 1 gallon of gasoline

kvv77 [185]

Answer:

127529 KJ

Explanation:

Since 1gallon = 3.78 L= 3780 ml

The density of C8H18= 0.703 g/mL

Density = mass/volume

Mass= Density × volume

Mass= 0.703 g/mL × 3780 ml

Mass= 2657.34 g

Molar mass of C8H18= 114 g/mol

Number of moles= mass/molar mass

Number of moles= 2657.34/114

Number of moles= 23.31 moles

Since 1 mole evolved=5471 kJ

23.31 moles = 5471 kJ × 23.31 = 127529 KJ

8 0

3 years ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

Answer: The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

Explanation:

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

3 years ago