Answer:
Answers are given below
Explanation:
(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.
So, butanal produces butanol on reaction with sodium borohydride in methanol.
(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.
(c) Aldehydes are oxidized by potassium dichromate in dil. sulphuric acid to produce carboxylic acid.
(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.
(e) Aldehyde gives condensation reaction with
to produce imine.
Structures of products for the given reaction has been shown below.
Which eclipse was modeled when the large ball was between the small ball and the light?
The model is a "Lunar Eclipse" (If it was talking about the earth, then yes, it is a lunar eclipse).
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Which eclipse was modeled when the small ball was between the large ball and the light?
The model is a "Solar Eclipse".
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What does the large ball represent?
The earth.
<u> </u>
What does the small ball represent?
The moon.
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What does the light source represent?
The sun.
Hope this helps!~ <3
(I can't draw so sorry.)
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Answer:
127529 KJ
Explanation:
Since 1gallon = 3.78 L= 3780 ml
The density of C8H18= 0.703 g/mL
Density = mass/volume
Mass= Density × volume
Mass= 0.703 g/mL × 3780 ml
Mass= 2657.34 g
Molar mass of C8H18= 114 g/mol
Number of moles= mass/molar mass
Number of moles= 2657.34/114
Number of moles= 23.31 moles
Since 1 mole evolved=5471 kJ
23.31 moles = 5471 kJ × 23.31 = 127529 KJ
<u>Answer:</u> The solubility product of silver (I) phosphate is 
<u>Explanation:</u>
We are given:
Solubility of silver (I) phosphate = 1.02 g/L
To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:
Molar mass of silver (I) phosphate = 418.6 g/mol

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The chemical equation for the ionization of silver (I) phosphate follows:
3s s
The expression of
for above equation follows:

We are given:

Putting values in above expression, we get:

Hence, the solubility product of silver (I) phosphate is 