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Alexxandr [17]
3 years ago
9

What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?

Chemistry
1 answer:
Zigmanuir [339]3 years ago
4 0
Molar mass CaCl₂ = 110.98 g/mol

number of moles :

n = m / molar mass

n = 330 / 110.98

n =2,9735 moles

Molarity ( M ) = moles solute / liters solution

M = 2.9735 / 1

M = 2.9735 mol/L⁻¹

<span>hope this helps!</span>
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a gas sample occupies a volume of 140 mL at a temperature of 296 K and a pressure of 98.2kPa. how many moles of gas are there? s
Tamiku [17]

Answer:

0.00559 mol

Explanation:

The following data were obtained from the question:

V = 140mL = 0.14L

T = 296K

P = 98.2kPa = 98200Pa

Recall: 101325Pa = 1atm

98200Pa = 98200/101325 = 0.97atm

R = 0.082atm.L/Kmol

n =?

The number of mole (n) can be obtained as follows:

PV = nRT

n = PV /RT

n = (0.97x0.14)/(0.082x296)

n = 0.00559 mol

Therefore, the number of mole of the gas present is 0.00559 mol

4 0
3 years ago
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3 years ago
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
3 years ago
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brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
Which of the following is not an example of a renewable resource?
Mazyrski [523]

Answer:

The answer is C. Coil

Explanation:

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5 0
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