The number of hydrogen ions would equal the number of hydroxide ions in a solution with a pH of what?

Why are most household items made up of oxygen?

Alchen [17]

It is in our atmosphere

5 0

3 years ago

A mixture of water and acetone at 756 mm boils at 70.0°C. The vapor pressure of acetone is

Tatiana [17]

Given :

A mixture of water and acetone at 756 mm boils at 70.0°C.

The vapor pressure of acetone is 1.54 atm at 70.0°C, while the vapor pressure of water is 0.312 atm at the same temperature.

To Find :

The percentage composition of the mixture.

Solution :

By Raoult's law :

$P=x_{acetone}P^o_{acetone}+x_{water}P^o_{water}\\\\x_{acetone}1.58+x_{water}0.312=\dfrac{756}{760}=0.995\ atm\\\\1.58x_a+0.312x_w=0.995$ ......( 1 )

Also , $x_a+x_b=1$ ......( 2 )

Solving equation 1 and 2 , we get :

$x_a=0.54\ and \ x_w=0.46$ .

Mass of acetone ,

$m_a=x_a\times MM_a\\\\m_a=0.54\times 58\\\\m_a=31.32\ g$

Mass of water ,

$m_w=x_w\times MM_w\\\\m_w=0.46\times 18\\\\m_a=8.28\ g$

$\%water =\dfrac{8.28}{8.28+31.32}\times 100\\\\\%water =20.9\%\\\\\%acetone =79.1\%$

Hence , this is the required solution.

6 0

3 years ago

Write a net ionic equation for the reaction that occurs when aqueous solutions of nitric acid and sodium hydroxide are combined.

Veronika [31]

Answer:

H^+(aq) + OH^-(aq) -------> H2O(l)

Explanation:

We must first write the molecular reaction equation as follows;

HNO3(aq) + NaOH(aq) ------>NaNO3(aq) + H2O(l)

The complete ionic equation is;

H^+(aq) + NO3^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + NO3^-(aq) + H2O(l)

The net ionic equation therefore is;

H^+(aq) + OH^-(aq) -------> H2O(l)

5 0

3 years ago

What happens to the speed of an object when dropped at free fall?

Liono4ka [1.6K]

Therefore, the rotation of the object "speeds up" as it falls. Therefore, it rotates "faster" than the Earth under it, and so it falls slightly to the east.

7 0

3 years ago

How much pure antifreeze must be added to 8 gallons of 10% antifreeze to make a 50% antifreeze solution?

QveST [7]

Answer: The amount of pure antifreeze that must be added is 6.4 gallons

Explanation:

We are given:

Percent of antifreeze given = 10 %

Amount of solution = 8 gallons

Let the amount of pure antifreeze be 'x'

Calculating the amount of pure antifreeze:

$0.1=\frac{x}{8}\\\\x=(0.1\times 8)=0.8$

Let the amount of pure antifreeze added in the solution be 'y'

Percent of solution to be made = 50 %

So,

$0.5=\frac{0.8+y}{8+y}\\\\0.5(8+y)=(0.8+y)\\\\y=6.4$

Hence, the amount of pure antifreeze that must be added is 6.4 gallons

5 0

3 years ago