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Lisa [10]
3 years ago
6

A 3.00 × 10^−9-coulomb test charge is placed near

Physics
2 answers:
viktelen [127]3 years ago
8 0

Answer:

B

Explanation:

Given:-

- The charge of the test particle q = 3.0 * 10^-9 C

- The force exerted by the metal sphere F = 6.0 * 10^-5 N

Find:-

The magnitude and direction of the electric field strength at this location?

Solution:-

- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:  

                                       F = E*q

- Using the data given we can determine E:

                                       E = F / q

                                       E = (6.0 * 10^-5) / (3.0 * 10^-9)

                                       E = 20,000 N/C

- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.

patriot [66]3 years ago
3 0

Answer:

(2)  2.0×10⁴ N/C directed towards the  sphere

Explanation:

Electric Field: This can be defined as the force per unit charge. The S.I unit of Electric Field is N/C.

The expression for electric Field is given as,

E = F/q...................... Equation 1

Where E = Electric Field, F = Force, q = charge.

Given: F = 6.0×10⁻⁵  N, q = 3×10⁻⁹ C

Substitute into equation equation 1

E = 6.0×10⁻⁵/(3×10⁻⁹)

E = 2.0×10⁴ N/C directed towards the  sphere

Hence the right option is  (2)  2.0×10⁴ N/C directed towards the  sphere

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State Archimedes' principle.
vampirchik [111]

Answer:

Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body.

Explanation:

Archimedes' principle allows the buoyancy of an object partially or fully immersed in a fluid to be calculated. The downward force on the object is simply its weight. Thus, the net force on the object is the difference between the magnitudes

of the buoyant force and its weight. If this net force is positive, the object rises; if negative, the object sinks; and if zero, the object is neutrally buoyant - that is, it remains in place without either rising or sinking. In simple words,

8 0
3 years ago
Read 2 more answers
Which of the following statements is true? During heat flow, energy is converted to matter.
TEA [102]

Answer:

During heat flow, much of the energy is dissipated and cannot be used for useful work.

Explanation:

Which of the following statements is true?

During heat flow, much of the energy is lost.

During heat flow, energy is converted to matter.

During heat flow, much of the energy is dissipated and cannot be used for useful work.

3 0
3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Fofino [41]

Answer:

Force will be acting southward and the magnitude of force will be 1000 N

Explanation:

given,

mass of car = 1000 Kg

initial speed of the car (u) = 20 m/s

final speed of the car (v) = 0 m/s

distance to stop the car = 200 m

using equation of motion

v² = u² + 2 a s

0 = 20² + 2 x a x 200

400 a = -400

a = -1 m/s²

Now, we know

Force = mass x acceleration

F = 1000 x -1

F = -1000 N

- ve sign of force represent force will be acting in the opposite direction of motion.

Force will be acting southward and the magnitude of force will be 1000 N

6 0
3 years ago
You use a wedge that has a width of 1.1 in and a slope length of 3.3 in. What
xxTIMURxx [149]

Answer:

D. 3

Explanation:

First of all the mechanical advantage of a wedge is defined as the ratio of its slope length to its width.

Mathematically,

IMA = \frac{L}{W}

where,

IMA= Mechanical Advantage

L= slope length, and

w= width.

Given that,

slope length, L= 3.3 inches, and

width ,W= 1.1 inches

Then,

Mechanical Advantage, IMA

=  \frac{3.3}{1.1} = 3

3 0
3 years ago
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
ozzi

Answer:

The total work that the rope does to Mangnus is - 5780 Jules.

Explanation:

By definition, the work is defined as:

W=F.d

Where F and d are the force and the total displacement. Note that in the definition the product is a scalar product since F and d are both vectors.  

Take into account that according to third Newton's law the force that the rope does to Magnus is opposite to the force that Magnus does to the rope, therefore the scalar product will be negative due the rope's force goes against to Magnus displacement.  

For calculating the work, we take 2500 N as the value for the force and 2.312 meters as the value for the displacement:

W=-2500 N * 2.312 m

W=-5780 Nm = -5780 J

7 0
3 years ago
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