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2 years ago

10

The winning car in a race beat the second car by 19/100 of a second. The third car was 4/10 of a second behind the second car. B

y how much did the first car beat the third car?

1 answer:

Flura [38]2 years ago

8 0

Answer:

21/100 of a second

Step-by-step explanation:

4/10 = 40/100

40/100 - 19/100 = 21/100

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You can answer only this question, it's ok:

Sophie [7]

1)100 or A
Angle = |30*H - (11/2)*M|, where H is the hours hand and M is the minutes hand

in this case: H = 4, M= 40
30*4 - (11/2)*40 = 120 - 220 = -100 = |-100| = 100
2)x=4y or C
If you plug in 0,0 you will get 0=4×0 or 0,0

7 0

3 years ago

A fair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the pro

AnnyKZ [126]

First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3

So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3

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3 years ago

scarlet is trying to find the height of a dam. she stands 90 meters away from the dam and records the angle of elevation to the

Harlamova29_29 [7]

Make a drawing with a right triangle.

The opposite side, y, is the height of the dam less 1.65 m

The base or adjacent side is 90 m

The angle between the two sides is 90 m.

Then tan (26) = y / 90

y = 90 tan(26) = 90 (0.4877) = 43.90 m

The height of the dam is 43.90m + 1.65m = 45.55 m

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3 years ago

What’s is the answer

Natasha_Volkova [10]

Answer:

In simplest form, it should be:

3:2

6 / 2 = 3

4 / 2 = 2

Hope this helps!

8 0

3 years ago

find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho

____ [38]

For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.

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3 years ago