First we need to know how much each pen costs. So we take 11.77 and divide it by 11. That gives us 1.07 per pen. So answer choice A has 4 pens for 4.44, so we need to multiply 1.07 x 4. That gives you 4.28, so we know that isn't the correct answer. For option B, we need to multiply 1.07 x 5. That is 5.35, so that also can't be the answer. For C, we need to do 1.07 x 6, and that gives us 6.42. So we know the correct answer is option C.
So 5/8 inches to milimeters
we know that 1 in=2.54 cm so
5/8 in times 2.54= 1.5875 cm
1 cm=10 mm
1.5875 cm times 10=15.875mm aprox 16 mm, but best to go smaller since it won't fit if bigger
answer: 16mm (my recomendation would be 15mm)
Answer:
30
Step-by-step explanation:
For a = <xa, ya> and b = <xb, yb>, the dot product is the sum of products ...
a·b = (xa)(xb) + (ya)(yb)
Substituting the given information, you have ...
a·b = 5·4 + 2·5 = 20 + 10
a·b = 30
_____
Some graphing calculators can do such math. There are also dot product calculators available on the Internet. If you have quite a few of these to calculate, you can put the appropriate formula into a spreadsheet.
Answer: g(x) = 3/2 x + 9
Step-by-step explanation:
h(x) = -2/3 x - 1
perpendicular lines always have the opposite sign, reciprocal slope
so, the slope of the perpendicular line would be: m = 3/2
y = mx + b
y = 3/2 x + b
plug in (-4, 3) to find b
3 = 3/2 (-4) + b
3 = -6 + b
b = 9
y = 3/2 x + 9
g(x) = 3/2 x + 9
Answer: <u>110 feet per second</u>
Step-by-step explanation:
In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.
Now we can calculate the speed of the trains in feet per second so:


So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:


Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.