Question

Please help me i would greatly appreciate it.. 50 points and will mark brainliest

Answer 1

Answer:

368.92g

Explanation:

Firstly, let's balance the equation which is

2NO + O₂ ---> 2NO₂

Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio

2NO + O₂

2 : 1

8.02 mol : x mol

Moles of O₂ = 8.02 ÷ 2 = 4.01 mol

Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO

2NO + O₂

2 : 1

x mol : 18.75 mol

Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂

Using 8.02 mol of NO to figure out the number of moles of NO₂ :

2NO : 2NO₂

They have the same molar ratio of 2 : 2, so the number of moles is 8.02

Using formula moles = mass / Molar mass

Rearranging to find mass = moles × molar mass

Molar mass of NO₂ = 14 + 16 + 16 = 46

Mass = 46 × 8.02 = 368.92g

Answer 2

Reaction:

2NO + O₂ → 2NO₂

determine the limiting reactant from the ratio of moles to the reaction coefficient

NO : O₂ = 8.02/2 : 18.75/1 = 4.01 : 18.75

NO as a limiting reactant (smaller ratio)

so mole NO₂ from limiting reactant (NO) :

= 2/2 x mole NO

= 2/2 x 8.02

= 8.02

mass NO₂ = mole x molar mass NO₂ = 8.02 x 46 g/mole = 368.92 g