All categories

2 years ago

Please help me i would greatly appreciate it.. 50 points and will mark brainliest

Chemistry

2 answers:

Nikitich [7]2 years ago

5 0

Answer:

368.92g

Explanation:

Firstly, let's balance the equation which is

2NO + O₂ ---> 2NO₂

Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio

2NO + O₂

2 : 1

8.02 mol : x mol

Moles of O₂ = 8.02 ÷ 2 = 4.01 mol

Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO

2NO + O₂

2 : 1

x mol : 18.75 mol

Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂

Using 8.02 mol of NO to figure out the number of moles of NO₂ :

2NO : 2NO₂

They have the same molar ratio of 2 : 2, so the number of moles is 8.02

Using formula moles = mass / Molar mass

Rearranging to find mass = moles × molar mass

Molar mass of NO₂ = 14 + 16 + 16 = 46

Mass = 46 × 8.02 = 368.92g

Andreyy892 years ago

4 0

Reaction:

2NO + O₂ → 2NO₂

determine the limiting reactant from the ratio of moles to the reaction coefficient

NO : O₂ = 8.02/2 : 18.75/1 = 4.01 : 18.75

NO as a limiting reactant (smaller ratio)

so mole NO₂ from limiting reactant (NO) :

= 2/2 x mole NO

= 2/2 x 8.02

= 8.02

mass NO₂ = mole x molar mass NO₂ = 8.02 x 46 g/mole = 368.92 g

You might be interested in

For each compound determine whether it is organic or inorganic. C10h16kno9s2 naaso2 hsicl3 (ch)4as2 (bio)2co3 h2p2o7 h2o co2 c6h

Sindrei [870]

a. Organic: C₁₀H₁₆KNO₉S₂; (CH₃)₄As₂; C₆H₁₂O₆

b. Inorganic: NaAsO₂; HSiCl₃; (BiO)₂CO₃; H₂P₂O₇; H₂O; CO₂

Compounds containing <em>both C and H</em> are organic.

Compounds that are <em>not organic</em> are inorganic.

8 0

3 years ago

As the energy of the molecules increases, the motion of the molecules _______.

Alexus [3.1K]

Answer:

the motion of molecules increases

6 0

3 years ago

Consider an amphoteric hydroxide, m(oh)2(s), where m is a generic metal. estimate the solubility of m(oh)2 in a solution buffere

Colt1911 [192]

Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7
∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
= (2x10^-16)/(1x10^-7)^2
= 0.02 M
b) at PH =10
when POH = 14- PH = 14-10 = 4
when POH = -㏒[OH-]
    4 = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
= 2x10^-16 / (1x10^-4)^2
  = 2x10^-8 M
c) at PH= 14
when POH = 14-PH
= 14 - 14
= 0
when POH = -㏒[OH]
  0 = - ㏒[OH]
∴[OH] = 1 m
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
= (2x10^-16) / 1^2
= 2x10^-16 M

8 0

4 years ago

Compute the values of the diffusion coefficients for the interdiffusion of carbon in both α-iron (BCC) and γ-iron (FCC) at 900°C

bogdanovich [222]

Answer:

α-iron (BCC) has faster diffusion rate because of lower values in activation energy and pre-exponential value.

Explanation:

Taking each parameters or data at a time, we can determine the values/a constant for each parameters in the diffusion coefficient equation.

For α-iron (BCC), the diffusion coefficient = pre-exponential value,Ao × e^( -Activation energy,AE)/gas constant,R × Temperature.

Converting the given Temperature, that is 900°C to Kelvin which is equals to 1173.15K.

For α-iron (BCC), the pre-exponential value, Ao = 1.1 × 10^-6, and the activation energy, AE = 87400.

Thus, we have that the diffusion coefficient = 1.1 × 10^-6 × e(-87400)/1173.15 × 8.31.

Diffusion coefficient for α-iron (BCC) = 1.41 × 10^-10 m^2/s.

Also, For the γ-iron (FCC), the pre-exponential value, Ao = 2.3 × 10^-5 and the activation energy, AE = 148,00.

From these values we can see that both the exponential value, Ao and the activation energy for γ-iron (FCC) are higher than that of α-iron (BCC).

Thus, the diffusion coefficient for the γ-iron (FCC) = 2.3 × 10^-5 × e ^-(14800)/8.31 × 1173.15.

Then, the diffusion coefficient for the γ-iron (FCC) = 5.87 × 10^-12 m2/s.

Therefore, there will be faster diffusion in α-iron (BCC) because of lower activation energy and vice versa.

6 0

3 years ago

What does the most accurate clock tell us

Murrr4er [49]

It tell us the most accurate time u can get out of a clock

6 0

4 years ago

Read 2 more answers