A runner achieves a velocity of 11.1 m/s nine seconds after he begins. What is his acceleration
2 answers:
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Answer:
a) The minimum thickness of the oil slick at the spot is 313 nm
b) the minimum thickness be now will be 125 nm
Explanation:
Given the data in the question;
a) The index of refraction of the oil is 1.20. What is the minimum thickness of the oil slick at that spot?
t = λ/2n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.20
we substitute
t = 750 / 2(1.20)
t = 750 / 2.4
t = 312.5 ≈ 313 nm
Therefore, The minimum thickness of the oil slick at the spot is 313 nm
b)
Suppose the oil had an index of refraction of 1.50. What would the minimum thickness be now?
minimum thickness of the oil slick at the spot will be;
t = λ/4n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.50
we substitute
t = 750 / 4(1.50)
t = 750 / 6
t = 125 nm
Therefore, the minimum thickness be now will be 125 nm
Answer:
Explanation:
We know that acceleration is change in velocity over time.
v is the final velocity and u is the initial velocity.
Solve for v.
Multiply both sides by t.
Add u to both sides.
Answer:
= 40 cm
Explanation:
given data
string length = 30 cm
solution
we take here equation of length that is
L = ...............1
so
total length will be here
so will be
= 40 cm