Answer:
m = 1.35 kg
Explanation:
- In absence of friction, total mechanical energy must be conserved, so the sum of the initial elastic potential energy plus the initial kinetic energy, must be equal to the sum of the final kinetic energy plus the final elastic potential energy, as follows:
- As the block starts from rest, this means that Ki =0.
- We can express the elastic potential energy at any point , as follows:
where k is the spring constant = 60.0 N/m, and Δx is the distance from
the equilibrium position.
- Replacing Ui, Uf and Kf in (1), we have:
- Replacing by the givens, and solving for m, we get:
m =1.35 kg
Answer:
T = 51.6 N
Explanation:
We know that maximum tension in vertical circular motion is at the bottom position and thus;
T − Mg = F_c = Mv²/r
Where F_c is centripetal force
Since T − Mg = Mv²/r
Let's make T the subject;
T = Mg + Mv²/r
Where;
T is tension of the string
M is mass of stone
v is speed of stone
r is length of chord
g is acceleration due to gravity which is 9.8 m/s²
From the question,
M = 2Kg
v = 4 m/s
r = 1m
Plugging in the relevant values we can obtain T;
T = M(g + v²/r) = 2(9.8 + 4²/1)
T = 2(9.8 + 16)
T = 51.6N
Answer:
Acceleration=24.9ft^2/s^2
Angular acceleration=1.47rads/s
Explanation:
Note before the ladder is inclined at 30° to the horizontal with a length of 16ft
Hence angular velocity = 6/8=0.75rad/s
acceleration Ab=Aa +(Ab/a)+(Ab/a)t
4+0.75^2*16+a*16
0=0.75^2*16cos30°-a*16sin30°---1
Ab=0+0.75^2sin30°+a*16cos30°----2
Solving equation 1
(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s
Also from equation 2
Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2
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