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2 years ago

Hey anyone here I'm ban 2 mint ago my I'd is aron7 I talk to Rachel anybody present therw

Physics

2 answers:

pishuonlain [190]2 years ago

8 0

sign out and log in again...if does not work then make a new account

gtnhenbr [62]2 years ago

5 0

Answer:

follow me and mark me brainliest

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An electric motor with a 1200 hp output drives a machine with an efficiency of 60%. What is the energy output of the machine per

kirill [66]

Answer:

536,904 J/s

Explanation:

The energy output from motor is the input energy in the machine.

We know that efficiency is percentage energy ouput to energy input, and expressed as

$n=\frac {E_o}{E_i}$

Where n and E represent efficiency and energy respectively, subscripts o and i represent output and input respectively. Since for the machine we have the input energy then the output will be the product of efficiency and input energy

Energy output=0.6*1200 hp=720 hp

Converting hp to J/s we multiply by 745.7

Energy is 720*745.7=536,904 J/s

4 0

2 years ago

The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh

Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

$v^2=v^2_o-2ax$

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

$\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}$

Next, consider that the formula for the force is:

$F=ma$

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

$F=(820kg)(0.66\frac{m}{s^2})=542.20N$

Hence, the required force to stop the car is 542.20N

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1 year ago

Mode of physical activity <br> A.frequency <br> B.intensity <br> C.time <br> D.type

Artyom0805 [142]

A.frequency

That's the answer

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2 years ago

How do I find the approximate velocity of "the object", on the graph at 5 seconds?

MakcuM [25]

First, foremost, and most critically, you must look at the graph, and critically
examine its behavior from just before until just after the 5-seconds point.

Without that ability ... since the graph is nowhere to be found ... I am hardly
in a position to assist you in the process.

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3 years ago

What is a linguist? in terms of forensic.

nadya68 [22]

It is either a person who studies Linguistics or

a person skilled in foreign languages

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3 years ago

Hey anyone here I'm ban 2 mint ago my I'd is aron7 I talk to Rachel anybody present therw​

Hey anyone here I'm ban 2 mint ago my I'd is aron7 I talk to Rachel anybody present therw