Answer:
(a) The velocity of the car before the brakes were applied is 77.46 ft/s
(b) The time required for the car to stop is 7.8 s
Explanation:
Given;
acceleration of the car, a = 10 ft/s²
distance traveled by the car, d = 300 ft
(a) the velocity of the car before the brakes were applied is given;
v² = u² + 2ad
v² = 0 + 2(10 x 300)
v² = 6000
v = √6000
v = 77.46 ft/s
(b) the time required for the car to stop
d = ut + ¹/₂at²
d = 0 + ¹/₂at²
d = ¹/₂at²
t² = 2d / a
t = √ ( 2d / a)
t = √ ( 2 x 300 / 10)
t = 7.8 s
Therefore, the time required for the car to stop is 7.8 s
Answer:
Following are the responses to the given question:
Explanation:
The mass (mg) is downwards, the typical pressure is upward. This pushing force of is pushed forward by skater 3 on skater 2. (considered as rightward direction). The strength of the slater 2 in reply is the slater Skater three moves to the left.
Its push force imparted to the skateboarder 2 in relation those above forces The force on skater 2 by skater 1 is as a response, to a left. Skater 2's free body system is as follows:
Answer:
Explanation:
Given
altitude of the Plane
When Airplane is away
Distance is changing at the rate of
From diagram we can write as
differentiate above equation w.r.t time
as altitude is not changing therefore
at
substitute the value we get
A group of cats is called a clowder.