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2 years ago

2. If an em' of Hg weighs 13.6 g, what is the mass of a cylinder of: Sem and height 20 Cm

Physics

1 answer:

Yuri [45]2 years ago

8 0

Answer:

Let the mass of mercury m= 13.6 gm and volume be V=1cm3.

Now change in volume when it is heated upto 50oC,

ΔV=VαΔT

ΔV=1×1.82×10−4×50

ΔV=91×10−4cm3

New volume V1=V+ΔV=1.0091cm3

New density ρ=V1m=1.009113.6=13.48gcm−3

Explanation:

Mark me as a brainliest please

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lutik1710 [3]

Answer:

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2 years ago

Que es electromagnetico?

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Se llaman cuerpos eléctricos.

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3 years ago

A ball of mass M collides with a stick with moment of inertia I = βml2 (relative to its center, which is its center of mass). Th

ZanzabumX [31]

Answer:

Part a)

$v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}$

Part b)

$v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})$

Explanation:

Since the ball and rod is an isolated system and there is no external force on it so by momentum conservation we will have

$Mv_o = M v_1 + m v_2$

here we also use angular momentum conservation

so we have

$M v_o d = M v_1 d + \beta mL^2 \omega$

also we know that the collision is elastic collision so we have

$v_o = (v_2 + d\omega) - v_1$

so we have

$\omega = \frac{v_o + v_1 - v_2}{d}$

also we know

$M v_o d - M v_1 d = \beta mL^2(\frac{v_o + v_1 - v_2}{d})$

also we know

$v_1 = v_o - \frac{m}{M}v_2$

so we have

$M v_o d - M(v_o - \frac{m}{M}v_2)d = \beta mL^2(\frac{v_o + v_o - \frac{m}{M}v_2 - v_2}{d})$

$mv_2 d = \beta mL^2\frac{2v_o}{d} - \beta mL^2(1 + \frac{m}{M})\frac{v_2}{d}$

now we have

$(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})v_2 = \frac{2\beta mL^2v_o}{d}$

$v_2 = \frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})}$

Part b)

Now we know that speed of the ball after collision is given as

$v_1 = v_o - \frac{m}{M}v_2$

so it is given as

$v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})$

3 0

3 years ago

Your mom is making lunch which forces are acting on your mom

N76 [4]

The forces acting on your mom while cooking is Air resistance and the force of friction

Explanation:

1. Air resistance:

In simple words, Air resistance can be stated as the type of friction between the air and the other materials.
In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

2. The force of friction:

In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

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3 years ago

Read 2 more answers

What is acceleration produced by a force of 12 newton exerted on an object of mass 3kg

jarptica [38.1K]

Answer:

a=F/m

a=12N/3kg (here newton can be written as kgm/s^2 so kg will be cancelled)

a=4m/s^2

Explanation:

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3 years ago