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Nastasia [14]
3 years ago
15

_____ is the preceived frequency of a sound wave.​

Physics
1 answer:
Lina20 [59]3 years ago
7 0
I guess the answer is pitch
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What is center of curvature<br>​
nataly862011 [7]

Answer:

the centre of a circle which passes through a curve at a given point and has the same tangent and curvature at that point is called Center of Curvature.

6 0
3 years ago
If two tiny identical spheres attract each other with a force of 2.00 nn when they are 20.0 cm apart, what is the mass of each s
attashe74 [19]

The mass of each sphere is m=1.7kg

<h3>What is the mass?</h3>

The amount of matter in a particle or object is represented by the dimensionless quantity mass (symbolized m). The kilogram is the chosen unit of mass according to the International System (SI) (kg).

<h3>According to Given Information:</h3>

We'll apply the formula.

Now take note that the value we must discover is m1 = m2 = m. When m is solved for,

m=1.7kg is obtained using the formulas Fg = 2.0 109 N and G = 6.673 1011 N m2/kg2.

<h3>What is the force?</h3>

A force refers to the push or pull that such an object feels when it comes into contact with another object. A force is applied to each object when two things come into contact. The interaction between the two items stops when the force is no longer looks by either.

To know more about mass due to gravitation visit:

brainly.com/question/12528243

#SPJ4

6 0
2 years ago
A car of mass 1200 kg is traveling at 2 m/s. Then it collides with a heavy boulder in the road. During the collision, the car mo
olga2289 [7]

Answer:

F = 1.6*10⁴ N

Explanation:

Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.

Unknown: force F

Force is given by Newton's law:

(1) F = ma

The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.

The distance for an object starting from rest for a constant acceleration is given by:

(2) x=\frac{1}{2}at^2

The velocity for an object starting from rest for a constant acceleration:

(3) v=at

Using equation 2 and 3 to eliminate time t:

(4) x=\frac{1}{2}a\frac{v^2}{a^2}=\frac{v^2}{2a}

Solving equation 4 for the acceleration a:

(5) a=\frac{v^2}{2x}

Using equation1 to solve for the force F:

(6) F=ma=\frac{mv^2}{2x}

4 0
3 years ago
#4<br> HELP PLEASE!<br> Find Gravitational Potential Energy! <br> THANK YOU!
Scilla [17]

Answer:

\Delta GPE=-3.92\ 10^9\ J

Explanation:

<u>Gravitational Potential Energy</u>

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, g=9.8 m/sec^2

The mass of water is given as

m=8,000,000\ kg

The height above the rocks is h=50 m. Let's compute the GPE

GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)

GPE_1=3,920,000,000\ Joule

It should be expressed in scientific notation

GPE_1=3.92\ 10^9\ J

The GPE at the bottom, where h=0

GPE_2=0

The change of gravitational potential energy is:

\Delta GPE=GPE_2-GPE_1

\boxed{\Delta GPE=-3.92\ 10^9\ J}

8 0
3 years ago
Where did most of the comets in the Kuiper belt come from?
IgorC [24]

Answer:

The answer you would be looking for is A.

Explanation:

6 0
3 years ago
Read 2 more answers
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