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2 years ago

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To stay in a hotel it costs $104 each night (n) plus a $15 fee for parking. Think of the linear function that demonstrates the t

otal cost (C) of staying in the hotel in terms of the number of nights (n) stayed. whats the initial value ?

1 answer:

Anna007 [38]2 years ago

7 0

Answer:

the equation is: (104 * x) + 15 = y i believe

Step-by-step explanation:

104 OF THE NUMBER of nights so times x because you dont know the number

and + 15 because of the fee

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In circle C, r = 32 units.

vlabodo [156]

Probably 2561 but since area equal r^2 I thought it would be 3217

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3 years ago

2/5 ÷ 2/3 = 2/5 x _=_<br>

natali 33 [55]

Answer:

the answer is 1 I guess

Step-by-step explanation:

2/5 - 3/5

2-3/5

1

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3 years ago

Andre draws a tape diagram for 3÷2/3

bija089 [108]

Answer:

No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3

3 ÷ 2/3

= 3 × 3/2

= 9/2

= 4 1/2

Therefore, 3 divided by 2/3 is 4 1/2

Andre's reasoning is wrong.

Step-by-step explanation:

It is incorrect

Let's divide and compare the sum

3 : 2/3 = 3*3/2 = 9/2 = 4 1/2

and

There are four 2/3 fractions and one 1/3 fraction

The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2

4 0

2 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers

What is 6.564671128 x 10^-7 meters converted into nanometers?

fomenos

Answer:

656.4671128 nanometer

Step-by-step explanation:

1 nano meter = 10 ^-9 meter

Now given 6.564671128 × 10^ -7 meters

so in nano meter ,

$\frac{6564671128 times 10^-7}{10^9}$

= 656.4671128 × 10^-9 meter

= 656.4671128 nanometer Answer

3 0

3 years ago