Question

Sally is counting the people and animals that live on her farm. She, her brother, and her parents together have 18 cows, 1 horse, 10 goats, and no chickens. Sally picks one at random. Help her determine the likelihood of selecting each type of animal

Answer 1

Using it's concept, it is found that there is a:

• 0.6207 = 62.07% probability of selecting a cow.

• 0.0345 = 3.45% probability of selecting a horse.

• 0.3448 = 34.48% probability of selecting a goat.

• 0% probability of selecting a chicken.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there is a total of 18 + 1 + 10 + 0 = 29 animals, hence:

18/29 = 0.6207.

0.6207 = 62.07% probability of selecting a cow.

1/29 = 0.0345.

0.0345 = 3.45% probability of selecting a horse.

10/29 = 0.3448.

0.3448 = 34.48% probability of selecting a goat.

0/29 = 0.

0% probability of selecting a chicken.

More can be learned about the probability concept at brainly.com/question/15536019