Explanation:
Given that,
Mass of the shopping cart,
Initial speed of the shopping cart,
Mass of the box,
Initial speed of the box, (at rest)
They stick together and continue moving at a new velocity. It is a case of inelastic collision.
(a) The momentum of the shopping cart before the collision is given by :
(b) The momentum of the box before the collision is given by :
(c) The velocity of the combined shopping cart/box wreckage after the collision is given by using the conservation of momentum as :
Hence, this is the required solution.
Answer:3.6
Explanation:
Given
Architect decide to double the width
length increases by 50 percent
height increases by 20 percent
Let L,B,H be length,height and width of rectangular room
L'=1.5L
B'=2B
H'=1.2H
therefore new volume V'=L'\times B'\times H'
V'=3.6LBH
new volume is 3.6 times the original
<u>Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own. The detector’s search coil receives the retransmitted field and alerts the user by producing a target response. metal detectors are capable of discriminating between different target types and can be set to ignore unwanted targets.
</u>
1. Search Coil
The detector’s search coil transmits the electromagnetic field into the ground and receives the return electromagnetic field from a target.
2. Transmit Electromagnetic Field (visual representation only - blue)
The transmit electromagnetic field energises targets to enable them to be detected.
3. Target
A target is any metal object that can be detected by a metal detector. In this example, the detected target is treasure, which is a good (accepted) target.
<em>hope this helps PLEASE MARK AS BRAINLIEST:)</em>
Answer:
Install sound absorbers such as foam or acoustical panels
Explanation:
They could install some sound absorbers such as foam or acoustical panels in the walls, floors, and ceiling of the conference room.
Answer:
new atmospheric pressure is 0.9838 × Pa
Explanation:
given data
height = 21.6 mm = 0.0216 m
Normal atmospheric pressure = 1.013 ✕ 10^5 Pa
density of mercury = 13.6 g/cm³
to find out
atmospheric pressure
solution
we find first height of mercury when normal pressure that is
pressure p = ρ×g×h
put here value
1.013 × = 13.6 × 10³ × 9.81 × h
h = 0.759 m
so change in height Δh = 0.759 - 0.0216
new height H = 0.7374 m
so new pressure = ρ×g×H
put here value
new pressure = 13.6 × 10³ × 9.81 × 0.7374
atmospheric pressure = 98380.9584
so new atmospheric pressure is 0.9838 × Pa