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2 years ago

What substance would be soluble in water?

Chemistry

1 answer:

4vir4ik [10]2 years ago

7 0

Answer:

Explanation:

Since water is polar, we need for there to be a polar solute. This eliminates options B and D.

Now to choose between A and C, we can look at the compounds mentioned.

For A, NH3 is mentioned, which is a polar substance.

However, for C, H2 is mentioned, which is a nonpolar molecule, contrary to what is stated by the option.

Therefore, A is the answer.

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When liquid water evaporates to gaseous water

alina1380 [7]

Answer: liquid water 2

Explanation:

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3 years ago

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3 years ago

The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

Rina8888 [55]

<u>Answer:</u> The expression of $K_b$ is written below.

<u>Explanation:</u>

We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.

It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.

The chemical equation for the reaction of trimethylamine in water follows:

$(CH_3)_3N+H_2O\rightleftharpoons (CH_3)_3NH^++OH^-$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

Hence, the expression of $K_b$ is written above.

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3 years ago

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3 years ago

Read 2 more answers

How many moles at STP would take up 44.8 liters?

Tom [10]

Answer:

n = 2 mol

Explanation:

Given data:

Pressure = standard = 1 atm

Temperature = standard = 273.15 K

Volume = 44.8 L

Number of moles = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

1 atm × 44.8 L = n × 0.0821 atm.L/ mol.K × 273.15 K

44.8 atm.L = n × 22.43 atm.L/ mol

n = 44.8 atm.L / 22.43 atm.L/ mol

n = 2 mol

4 0

3 years ago