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emmasim [6.3K]
2 years ago
11

What is exactly the relation between a Rhombus, rectangle, parallelogram, and square explain please i will mark brainliest only

IF you explain
Mathematics
2 answers:
igomit [66]2 years ago
6 0

Answer:

Step-by-step explanation:

ch4aika [34]2 years ago
5 0

Any rhombus is a parallelogram, but not the other way around. If you were to make a Venn Diagram, the "rhombus" portion is entirely inside the set of "parallelograms".

The same can be said about rectangles as well. Any rectangle is a parallelogram, but not the other way around.

If we overlapped the region of rectangles and rhombuses, then we form the region for squares. A square is a combination of a rhombus and a rectangle.

Any square has all four sides the same length (property of a rhombus) and all angles equal to 90 (property of a rectangle). Since a square inherits properties of a rectangle and rhombus, it automatically makes any square a parallelogram.

Check out the venn diagram below.

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A b or c ? Help please
horsena [70]

Answer:

The second one I think

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How much sales tax will be charged at Store B?
bearhunter [10]

Answer:

7 %   $94.50(SALES TAX)   Question only asks for the SALES TAX THOUGH

Step-by-step explanation:

$1350.00 x .07 =$94.50

$94.50 is your sales tax on B

$1444.50 (total) x 15% gratuity  is $1444.50 x .15 = $216.68

$1444.50 + $216.68 =$1661.18  

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8 0
3 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
3 years ago
5x+5=10 what dose x =
Romashka [77]

Answer:0 becAusethere isno x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Rewrite V=lwh to isolate the variable w then the literal equation becomes w=v/lh true or false
Oduvanchick [21]

Answer:

True

Step-by-step explanation:

V=lwh\\\\lwh=V\\\\\frac{lwh}{lh}=\frac{V}{lh}\\\\  \boxed{w=\frac{V}{lh}};  l\neq  0

The answer should be true.

5 0
3 years ago
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