D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS
Answer:
23.52 m/s
Explanation:
The following data were obtained from the question:
Time taken (t) to reach the maximum height = 2.4 s
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =..?
At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)
was thrown as follow:
v = u – gt (since the rock is going against gravity)
0 = u – (9.8 × 2.4)
0 = u – 23.52
Collect like terms
0 + 23.52 = u
u = 23.52 m/s
Therefore, the rock was thrown at a velocity of 23.52 m/s.
Voltage = Current (I) × Resistance (R)
V = 10 × 28.5 = 285v
You didn't include the numerical value of speed.
Answer:
0.22 m
Explanation:
= Atmospheric pressure = 101325 Pa
= Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa
= height of the container = 7.59 m
= depth of the mercury
Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water
