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frosja888 [35]
2 years ago
8

Consider the circuit shown below V=18.00V. The terminal voltage of the battery is.

Physics
2 answers:
Pavel [41]2 years ago
6 0
Resistance is current x potential difference. So therefor run wafff
alexira [117]2 years ago
5 0
A) R= R1 + R2 + R3
So,
4 + 1 + 4= 9
b) I= V/R
So,
So,
18/9= 2 A
c) V= I x R
d) P= I*2 x R

I don’t know how to do the last two.

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A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull's-eye on a dart board. It hits at point Q
Kryger [21]
D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS
3 0
3 years ago
A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it was released.
Allisa [31]

Answer:

23.52 m/s

Explanation:

The following data were obtained from the question:

Time taken (t) to reach the maximum height = 2.4 s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)

was thrown as follow:

v = u – gt (since the rock is going against gravity)

0 = u – (9.8 × 2.4)

0 = u – 23.52

Collect like terms

0 + 23.52 = u

u = 23.52 m/s

Therefore, the rock was thrown at a velocity of 23.52 m/s.

7 0
3 years ago
What is the voltage in a circuit that has a current of 10.0 amps and a resistance of 28.5 ohms?
marin [14]
Voltage = Current (I) × Resistance (R)
V = 10 × 28.5 = 285v
6 0
3 years ago
In being served, a tennis ball is accelerated from rest to a speed of m/s. the average power generated during the serve is 2920
omeli [17]
You didn't include the numerical value of speed. 
6 0
3 years ago
A 7.59-m-tall container is filled to the brim, partway with mercury and the rest of the way with water. The container is open to
hoa [83]

Answer:

0.22 m

Explanation:

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa

h = height of the container = 7.59 m

x = depth of the mercury

Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water

P = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\2 P_{o} = P_{o} + \rho _{w} g (h - x) + \rho _{hg} g x\\P_{o} = \rho _{w} g (h - x) + \rho _{hg} g x\\101325 = (1000) (9.8) (7.59 - x) + (13600) (9.8) x\\x = 0.22 m

5 0
3 years ago
Read 2 more answers
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