Answer:
Explanation: the module will end up working out when you mix NO2CI and CI
Moles = mass(g) / ar
Reconfigure the eqn to
Mass(g) = Moles × ar
Imput the info you have and the ar of Mn and you should be able to get your ans. Sorry, i dont have a calculator with me.
Answer:
The final temperature of the iron is:- 38.0 °C
Explanation:
The initial temperature = 24.7 °C
Let Final temperature = T °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed by the iron = 85.7 J
C gas is the specific heat of the iron = 0.45 J/g °C
m is the mass of iron = 14.3 g
ΔT is the change in temperature. ( T - 24.7 ) °C
Applying the values as:
<u>Q = m C ×ΔT </u>
85.7 J = 14.3 g × 0.45 J/g °C × ( T - 24.7 ) °C
Solving for T, we get that:-
T = 38.0 °C
<u>The final temperature of the iron is:- 38.0 °C</u>
