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nordsb [41]
2 years ago
12

What is the least count of screw gauge and vernier calliper (9th grade) please help! ​

Physics
1 answer:
nadezda [96]2 years ago
7 0
The least count is the smallest unit of measurement which an instrument can take accurately
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An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
velikii [3]

Answer:

In free fall, mass is not relevant and there's no air resistance, so the acceleration the object is experimenting will be equal to the gravity exerted. If the object is falling on our planet, the value of gravity is approximately 9.81ms2 .

7 0
3 years ago
If the mass of a materials is 44grams and the volume of the material is 11cm^3 what would the density of the material be
jok3333 [9.3K]
Density =mass/volume
density= (0.044kg/(11 x10^-6)
4000kg/m^3
8 0
2 years ago
The acceleration due to gravity is 9.81 m/s2, towards the Earth. Rain falling from an altitude of 9,000 m would fall for about 1
Anna [14]

Answer:

the final speed of the rain is 541 m/s.

Explanation:

Given;

acceleration due to gravity, g = 9.81 m/s²

height of fall of the rain, h = 9,000 m

time of the rain fall, t = 1.5 minutes = 90 s

Determine the initial velocity of the rain, as follows;

h = ut + \frac{1}{2} gt^2\\\\9000 = 90u +  \frac{1}{2} (9.8)(90)^2\\\\9000 = 90u + 39690\\\\90u = -30690\\\\u = \frac{-30690}{90} \\\\u = -341 \ m/s

The final speed of the rain is calculated as;

v^2 = u^2 + 2gh\\\\v^2 = (-341)^2 + 2(9.8\times 9000)\\\\v^2 = 292681\\\\v = \sqrt{292681} \\\\v = 541 \ m/s

Therefore, the final speed of the rain is 541 m/s.

3 0
3 years ago
Read 2 more answers
A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 meter distance by applying a brake. No
kozerog [31]

Answer: -2502N

Explanation:

(V_2)^2=(V_1)^2+2ad

where;

V_2 = final velocity = 0

V_1 = initial velocity = 60 km/h = 16.67 m/s

a = acceleration

d = distance

First all of, because acceleration is given in m/s and not km/h, you need to convert 60km/h to m/s. Our conversion factors here are 1km = 1000m and 1h = 3600s

60km/h(\frac{1000m}{1km} )(\frac{1h}{3600s} )=16.67m/s

Solve for a;

(V_2)^2=(V_1)^2+2ad

Begin by subtracting (V_1)^2

(V_2)^2-(V_1)^2=2ad

Divide by 2d

\frac{(V_2)^2-(V_1)^2}{2d} =a

Now plug in your values:

a=\frac{(0)^2-(16.67 m/s)^2}{2(50m)}

a=\frac{0-277.89m^2/s^2}{100m}

a=-2.78m/s

If you're wondering why I calculated acceleration first is because in order to find force, we need 2 things: mass and acceleration.

F=ma

m = mass = 900kg

a = acceleration = -2.78m/s

F=(900kg)(-2.78m/s)\\F=-2502N

It's negative because the force has to be applied in the opposite direction that the car is moving.

8 0
3 years ago
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 55.0 min
nevsk [136]

Part a

The average speed = total distance traveled upon total time taken.

we know, distance =speed × time

Average speed = \frac{S_1t_1+S_2t_2+S_3t_3}{t_1+t_2+t_3+t_4}

insert the values:

S_1=80 km/hr\\
S_2=70 km/hr\\
S_3=55km/hr\\
t_1=55 min\\
t_2=10min\\
t_3=55min\\
t_4=55min

\frac{80\times 55+70\times10+55\times 55}{55+10+55+55} km/hr

= \frac{8125}{175} km/hr

= 46.43 km/hr

Hence, the average speed for the trip is 46.43 km/hr.

Part b

the total distance between two cities via this route would be the average speed times the total time taken = 46.43 km/hr × 2.9 hr = 134.65 km

(because 175 minutes = 2.9 hours)

Hence, the total distance between two cities via this route is 134.65 km.



7 0
3 years ago
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