Answer:
<em>Radius at liftoff 8.98 m</em>
Explanation:
At the working altitude;
maximum radius = 24 m
air pressure = 0.030 atm
air temperature = 200 K
At liftoff;
temperature = 349 K
pressure = 1 atm
radius = ?
<em>First, we assume balloon is spherical in nature,</em>
<em>and that the working gas obeys the gas laws.</em>
from the radius, we can find the volume of the balloon at working atmosphere.
Volume of a sphere = 
volume of balloon =
x 3.142 x
= 57913.34 m^3
using the gas equation,
= 
<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>
imputing values, we have
= 
0.03 x 57913.34 x 349 = 200V2
V2 = 606352.67/200 = <em>3031.76 m^3 this is the volume occupied by the gas in the balloon at liftoff.</em>
from the formula volume of a sphere,
V =
=
x 3.142 x
= 3031.76
4.19
= 3031.76
= 3031.76/4.19
radius r of the balloon on liftoff =
= <em>8.98 m</em>
Answer:
Fm is the net force down on the metal in air
Fm / 2 is the net force down on the metal in liquid
Fl is the buoyant force on the metal due to liquid
Fm - Fl = Fm / 2 equating upward and downward forces
Fm / 2 = Fl
The specific gravity of the metal is twice that of the liquid
Note: F = M g = ρ V g since ρ = M / V
At=v-u, where u=0
t= v/a=42/6 = 7
Answer: 7 seconds
Answer:
u= 29.43 m/s
h=44.14 m
Explanation:
Given that
t= 3 s
We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)
Initial velocity = u
Final velocity ,v= 0 (At maximum height)
We know v = u +a t
v=final velocity
u=initial velocity
a=Acceleration
Now by putting the values in the above equation
0 = u - 9.81 x 3
u= 29.43 m/s
The maximum height h is given as
v² = u ² - 2 g h
0² = 29.43 ² - 2 x 9.81 x h

h=44.14 m