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OleMash [197]
4 years ago
13

Which scientist used Tycho Brahe’s data to propose three laws of planetary motion?

Physics
2 answers:
AlladinOne [14]4 years ago
5 0

Hello Warkrat281,

The scientist who used Tycho Brahe's data to propose the three laws of planetary motion was "Johannes Kepler."

Sincerely, kittylike11

hope this helps!

slava [35]4 years ago
3 0
That was his student, Johannes Kepler.
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A weather balloon is designed to expand to a maximum radius of 24 m at its working altitude, where the air pressure is 0.030 atm
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Answer:

<em>Radius at liftoff 8.98 m</em>

Explanation:

At the working altitude;

maximum radius = 24 m

air pressure = 0.030 atm

air temperature = 200 K

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temperature = 349 K

pressure = 1 atm

radius = ?

<em>First, we assume balloon is spherical in nature,</em>

<em>and that the working gas obeys the gas laws.</em>

from the radius, we can find the volume of the balloon at working atmosphere.

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volume of balloon = \frac{4}{3} x 3.142 x 24^{3} = 57913.34 m^3

using the gas equation,

\frac{P1V1}{T1} = \frac{P2V2}{T2}

<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>

imputing values, we have

\frac{0.03*57913.34}{200} = \frac{1*V2}{349}

0.03 x 57913.34 x 349 = 200V2

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from the formula volume of a sphere,

V =  \frac{4}{3} \pi r^{3} =  \frac{4}{3} x 3.142 x r^{3} = 3031.76

4.19r^{3}  = 3031.76

r^{3} = 3031.76/4.19  

radius r of the balloon on liftoff = \sqrt[3]{723.57} = <em>8.98 m</em>

4 0
3 years ago
When a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g/2 (gravity over 2). Shaow that : de
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2 years ago
A rocket's acceleration is 6.0 m/s 2 . Assuming it starts at 0 m/s, how long will it take for the rocket to reach a velocity of
kupik [55]
At=v-u, where u=0

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A baseball was hit and reached its maximum height in 3.00s. Find (a) its initial velocity; (b) the height it reaches.[29.4 m/s;
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Answer:

u= 29.43 m/s

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Given that

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We know v = u +a t

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Now by putting the values in the above equation

0 = u - 9.81 x 3

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The maximum height h is given as

v² = u ² -  2 g h

0² = 29.43 ² - 2 x 9.81 x h

h=\dfrac{29.43^2}{2\times 9.81}\ m

h=44.14 m

4 0
4 years ago
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