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3 years ago

a 60 kg woman in a elevator is accelerating upward at a rate of 1.2 m/s2. What is the gravitational force acting upon the woman?

Physics

1 answer:

Flura [38]3 years ago

5 0

The gravitational force acting upon the woman is equal to -588.6N

Why?

To solve the problem, we need to consider that two forces are acting upon the woman, the first one is related to her weight and the second one is related to the acceleration of the elevator.

Gravitational force acting upon the woman:

$Force=m*gravityacceleration\\\\Force=60kg*-9.81\frac{m}{s^{2}}=-588.6N$

Hence, we have that the gravitational force acting upon the woman is equal to -588.6N.

Have a nice day!

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harkovskaia [24]

Answer:

Please see the given attachment.

Explanation:

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3 years ago

A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun

maxonik [38]

Answer:

The frequency heard by the motorist is 4313.2 Hz.

Explanation:

let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.

because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:

f1 = [(v + v2/(v - v1))]×(f2)

= [( 343 + 30)/(343 - 36)]×(3550)

= 4313.2 Hz

Therefore, the frequency heard by the motorist is 4313.2 Hz.

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3 years ago

A sixth grader moves down the hall at 1.2 m/s. When he sees a bunch of eighth graders coming, he

balandron [24]

Answer:

0.75m/s^2

Explanation:

3.6-1.2=2.4 m/s (Change in velocity)

2.4/3.2=0.75 m/s/s or m/s^2

5 0

3 years ago

The greater the mass is in an object, the higher resistance to a change in movement the object will have.

Bond [772]

True. Since Inertia states this law, we are bound to believe greater mass = greater resistance in change of motion

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3 years ago

Read 2 more answers

The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During whic

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Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) Formula of displacement= velocity x time

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is = $\frac{0+40}{2\\}$ {initial velocity + final velocity}

= $\frac{40}{2}$

=20

Therefore, the magnitude of the average velocity of the car is 20 m/s

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3 years ago