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3 years ago

Using the periodic table, choose the more reactive non-metal. S or As

Chemistry

2 answers:

8_murik_8 [283]3 years ago

5 0

S because As is not a non-metal

natulia [17]3 years ago

5 0

<u>Answer:</u> More reactive non-metal is Sulfur (S).

<u>Explanation:</u>

Non-metals are defined as the elements which have the tendency to gain electrons.

A reactive non-metal is the one which gains electrons easily.

In a periodic table, the reactivity of non-metals increases as we move across a period and decreases as we move down the group.

Sulfur belongs to group 16 and period 3 of the periodic table while Arsenic belongs to group 15 and period 4 of the periodic table.

Hence, Sulfur is a more reactive non-metal.

You might be interested in

What is the pressure in a 245 L tank that contains 5.21 kg of helium at 27 Celsius

Kitty [74]

<h2><u>Answer:</u></h2>

(These are not rounded to the correct decimal)

130.94 atm

13,266.6 kPa

99,571.4 mmHg

<h2><u>Explanation:</u></h2>

<u></u>

PV = nRT

V = 245L

P = ?

R = 0.08206 (atm) , 8.314 (kPa) , 62.4 (mmHg)

T = 273.15 + 27 = 300.15K

n = 1302.5 moles

How I found (n).

5.21kg x 1000g/1kg x 1 mole/4.0g = 1302.5 moles

Now, plug all the numbers into the equation.

Pressure in atm = (1302.5)(0.08206)(300.15) / 245 = 130.94 atm (not rounded to the correct decimal)

Pressure in kPa = (1302.5)(8.314)(300.15) / 245 = 13,266.6 kPa (not rounded to the correct decimal)

Pressure in mmHg = (1302.5)(62.4)(300.15) / 245 = 99,571.4 mmHg (not rounded to the correct decimal)

5 0

3 years ago

1. Complete the following

Marat540 [252]

Answer:

$\large \boxed{\text{0.603 mol}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 18.1

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{18.1 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1005 mol C$_{6}$H$_{12}$O}_{6}$

b) Moles of O₂

$\text{Moles of O}_{2} =\text{0.1005 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol O}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.603 mol O}_{2}\\\\\text{The reaction requires $\large \boxed{\textbf{0.603 mol}}$ of oxygen}$

3 0

3 years ago

Show all calculations. 1. 2 C 4 H 10 + 13 O 2 -> 8 CO 2 + 10 H 2 O a) what mass of O 2 will react with 400 g C 4 H 10? b) how

bazaltina [42]

$\\ \tt\hookrightarrow 2C_4H_10+13O_2\longrightarrow 8CO_2+10H_2O$

13mol of O_2 reacts with 2mols of C_4H_10.
7.5mol of O_2 reacts with 1mol of C_4H_10

No of moles:-

$\\ \tt\hookrightarrow \dfrac{Given\:mass}{Molar\:mass}$

$\\ \tt\hookrightarrow \dfrac{400}{58}$

$\\ \tt\hookrightarrow 6.89mol$

Now

Moles of O_2

$\\ \tt\hookrightarrow 7.5(6.89)=51.6mol$

Mass of O_2

$\\ \tt\hookrightarrow 51.6(32)=1651.2g$

4 0

2 years ago

Calculate the atomic mass of lead. The four lead isotopes have atomic masses and relative abundances of 203.973 amu (1.4%), 205.

blondinia [14]

207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu

2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu

8 0

3 years ago

Maya made this picture to represent a chemical reaction:

natka813 [3]

Answer:

2) It is neither a synthesis reaction nor a decomposition reaction because two reactants form two products.

Explanation:

This is not a synthesis reaction, which takes place when two or more reactants combine to form one product. This is a single replacement reaction, where the cation of an ionic compound "trades places" with another element that becomes the cation in a new ionic compound.

8 0

3 years ago