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umka2103 [35]
3 years ago
8

What is the force in N of an object that has a mass of 7 kilograms and an acceleration of 4 m/s/s

Physics
1 answer:
VMariaS [17]3 years ago
4 0

Newton's 2nd law of motion:         Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 4 m/s²,
then you will need to push it with (7 x 4) = 28 newtons of force.

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is a 1.5 V battery is connected in a simple circuit to a lightbulb with a resistance of 8 Ohms the amount of current flowing thr
adoni [48]
.1875 Amperes. 
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6 0
3 years ago
An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of
joja [24]

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

Given that

The wavelength of the wave, λ = 435 nm

Amplitude of the electric field, E(max) = 2.7*10^-3 V/m

a)

The frequency of the wave can be found by using the formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b)

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c)

1T = 1 (V.s/m^2)

8 0
3 years ago
Microwaves and infrared waves are similar because they both have
Orlov [11]
Microwave and Infrared Radiation. Both are forms of electromagnetic radiation. Both are transmitted as waves. Waves are converted to heat.
3 0
3 years ago
Determine the ratio of the flow rate through capillary tubes A and B (that is, QA/QB). The length of A is twice that of B, and t
Jet001 [13]

Answer:

\dfrac{Q_A}{Q_B}=0.031

Explanation:

Lets take

Radius of tube A=r

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Radius of tube B= r'

Length of tube B=L'

Given that

L = 2 L'

r= 0.5 r'

r' = 2 r

The pressure across tube given as

\Delta p=\dfrac{8\mu LQ}{\pi R^{4}}

\dfrac{L_AQ_A}{ R_A^{4}}=\dfrac{L_BQ_B}{ R_B^{4}}

\dfrac{Q_A}{Q_B}=\dfrac{R_A^4}{R_B^4}\times \dfrac{L_B}{L_A}

\dfrac{Q_A}{Q_B}=\dfrac{r^4}{(2r)^4}\times \dfrac{L'}{2L'}

\dfrac{Q_A}{Q_B}=\dfrac{1}{16}\times \dfrac{1}{2}

\dfrac{Q_A}{Q_B}=0.031

7 0
3 years ago
What will a spring scale read for the weight of a 75.0-kg woman in an elevator that moves upward with constant speed of 5.8 m/s
Sholpan [36]
<span>On the scale the only external forces are the man's weight acting downwards and the normal force which the scale exerts back to support his weight. So F = Ma = mg + Fs The normal force Fs (which is actually the reading on the scale) = Ma + Mg But a = 0 So Fs = Mg which is just his weight. Fs = 75 * 9.8 = 735N</span>
7 0
4 years ago
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